Question

您好我有这两个指标到目前为止运作良好：

-- --------------------------------------------
-- Nb Unique Accounts 
-- -------------------------------------------

    select count(distinct(O.user_id))
    from DB.order O LEFT JOIN DB.orderCompleted OrC
        ON O.id  = OrC.order_id
    where reason in ('2') 



-- --------------------------------------------
-- Nb Accounts that are eighter deactivated or invalid
-- -------------------------------------------

    select count(distinct(O.user_id))
    from DB.order O JOIN DB.orderCompleted OrC
        ON O.id  = OrC.order_id
    where reason (0,1)

问题＃1：我们现在需要一个第三个指标，它将计算已被停用或无效的帐户的nb百分比。我们怎么能实现这一点呢？

问题＃2：我们还希望只有一个大的SQL执行上面的所有3个小查询，然后使用这个联合或加入的大sql到商业智能报告工具，允许使用sql编码以显示它在crossTab

Answer 1

试试这个：

SELECT
    count(distinct CASE WHEN reason = 2 THEN O.user_id ELSE NULL END) AS "Nb Unique Accounts",
    count(distinct CASE WHEN OrC.Oder_id IS NOT NULL AND reason in (1,2) THEN O.user_id ELSE NULL END) AS "Nb Accounts deactivated/invalid",
    count(distinct CASE WHEN OrC.Oder_id IS NOT NULL AND reason in (1,2) THEN O.user_id ELSE NULL END) / count(distinct O.user_id) As "Percent deactived/invalid"
FROM DB.order O 
LEFT JOIN DB.orderCompleted OrC  ON O.id  = OrC.order_id

Answer 2

在

select count(distinct(O.user_id))
from DB.order O LEFT JOIN DB.orderCompleted OrC
    ON O.id  = OrC.order_id
where O.reason in ('2')

您正在计算表order中的用户ID，无论他们是否有相关的orderCompleted记录。您可以将其简化为：

select count(distinct user_id)
from DB.order
where reason = 2;

在查询中

select count(distinct(O.user_id))
from DB.order O JOIN DB.orderCompleted OrC
    ON O.id  = OrC.order_id
where reason (0,1)

你想要orderCompleted中的匹配。你可以简单地把它变成：

select count(distinct user_id)
from DB.order
where reason in (0, 1)
and id in (select order_id from ordercompleted);

要获得两个计数，请使用条件聚合。你也可以做数学：

select 
  count(distinct case when reason = 2 then user_id end),
  count(distinct case when reason in (0, 1) and id in (select order_id from ordercompleted) then user_id end),
  count(distinct case when reason in (0, 1) and id in (select order_id from ordercompleted) then user_id end) /
  count(distinct user_id)
from DB.order
where reason in (0, 1, 2);

或者将子查询移动到FROM子句：

select 
  count(distinct case when o.reason = 2 then o.user_id end),
  count(distinct case when o.reason in (0, 1) and oc.id is not null then o.user_id end),
  count(distinct case when o.reason in (0, 1) and oc.id is not null then o.user_id end) /
  count(distinct user_id)
from DB.order o
left join (select distinct order_id from ordercompleted) oc using (order_id)
where o.reason in (0, 1, 2);

Answer 3

嗨，这个伟大论坛的所有人。

请参阅rhis post消息的末尾，看看正确的MySql代码片段，我只能在一个大查询中找到。

另外，我正在进行LEFT JOIN的原因是因为订单O表中的数据可能在OrderCompleted OrC表中没有相应的数据。

@HLGEM：你的意思是

SELECT (col1/col2) AS Percent...
From ( Select col1, col2 from ...)
Where ...

- Nb独立帐户

select count(distinct(O.user_id)) 
from DB.order O LEFT JOIN DB.orderCompleted OrC ON O.id = OrC.order_id where O.reason in (2)

- Nb已停用或无效的帐户

select count(distinct(O.user_id))
from DB.order O JOIN DB.orderCompleted OrC ON O.id = OrC.order_id 
where O.reason in (0,1)

SQL - 2 SQL部分为1

3 个答案: