我正在尝试将数据发送到我的数据库,但没有发送任何内容。也没有显示任何连接错误。 PHP代码中也没有任何错误。 我为db dbh.inc.php创建了两个文件,一个公共连接文件 我在主要的php文件中调用过。
数据库连接:
<?php
$dbServername = "localhost";
$dbUsername = "root";
$dbPassword = "admin";
$dbName = "musicianshub";
$conn = mysqli_connect ($dbServername, $dbUsername, $dbPassword,$dbName);
PHP代码:
<?php
if (isset($_POST['submit'])) {
include 'dbh.inc.php';
$first = mysqli_real_escape_string($conn, $_POST['first']);
$last = mysqli_real_escape_string($conn, $_POST['last']);
$email = mysqli_real_escape_string($conn, $_POST['email']);
$phone = mysqli_real_escape_string($conn, $_POST['phone']);
$pwd = mysqli_real_escape_string($conn, $_POST['pwd']);
if (empty($first) || empty($last) || empty($email) || empty($phone) ||
empty($pwd)) {
header("Location: ../signup.php?signup=empty");
exit();
}
else {
if (!preg_match("/^[a-zA-Z]*$/", $fist) || !preg_match("/^[a-zA-
Z]*$/", $last)) {
header("Location: ../signup.php?signup=invalid");
exit();
}
else {
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
header("Location: ../signup.php?signup=email");
exit();
}
else {
$sql = "SELECT * FROM users WHERE user_phone='$user_phone'";
$result = mysqli_query($conn, $sql);
$resultCheck = mysqli_num_rows($result);
if ($resultCheck > 0) {
header("Location: ../signup.php?signup=phonetaken");
exit();
}
else {
$hashedPwd = password_hash($pwd, PASSWORD_DEFAULT);
$sql = "INSERT INTO users (user_first, user_last,
user_email, user_phone, user_pwd) VALUES ('$first',
'$last', '$email', '$phone', '$hashedPwd');";
mysqli_query($conn, $sql);
header("Location: ../signup.php?signup=success");
exit();
}
}
}
}
}
else {
header("Location: ../signup.php");
exit();
}
任何人都可以对它有所了解。 谢谢。