Question

我使用以下数组结构来创建一个带有节

的tableView

struct words {

    var sectionName : String!
    var coptic : [String]!
    var english : [String]!
}

var array = [words]()
var filtered = [words]()

array = [words(sectionName: "", coptic: [""], English: [""])]

我想使用类似代码的搜索控件

func updateSearchResults(for searchController: UISearchController) {
    // If we haven't typed anything into the search bar then do not filter the results
    if searchController.searchBar.text! == "" {
        filtered = array
    } else {
        // Filter the results
        filtered = array.filter { $0.coptic.lowercased().contains(searchController.searchBar.text!.lowercased()) }

    }

不幸的是，因为coptic是一个[String]，而不仅仅是一个String，所以代码不起作用。有没有办法修改它以便能够过滤搜索coptic子部分？

Answer 1

你可以这样做。

func updateSearchResults(for searchController: UISearchController) {
    // If we haven't typed anything into the search bar then do not filter the results
    if searchController.searchBar.text! == "" 
    {
        filtered = array
    }
    else 
    {
        filtered.removeAll()
        array.forEach({ (word:words) in

            var tempWord:words = words.init(sectionName: word.sectionName, coptic: [""], english: [""])
            let copticArray = word.coptic.filter({ (subItem:String) -> Bool in
                    let a = subItem.lowercased().contains(searchController.searchBar.text!.lowercased())
                    return a;
                })
            tempWord.coptic = copticArray
            filtered.append(tempWord)
        })

   }
}

输入数组=数组= [字数（sectionName：＆＃34; abc＆＃34;，coptic：[＆＃34; apple＆＃34;，＆＃34; ball＆＃34;，＆＃34; cat＆＃34; ;，＆＃34; dog＆＃34;]，英语：[＆＃34;＆＃34;]）]

搜索＆＃34; app＆＃34;

输出字（sectionName：abc，coptic：[＆＃34; apple＆＃34;]，英文：[＆＃34;＆＃34;]）]

如何将UISearchBarController与数组子部分一起使用

1 个答案: