例如: 我的Db商店跟随Json。表格跟随json我需要提取特定字段的值。
"student": [
{
"name": "Xyz",
"college": "abc",
"student_id":{
"$oid": "59a9314f6d0000920962e247"
}},
{
"name": "DDD",
"college": "opop",
"student_id":{
"$oid": "59a9314f6d0000920962e257"
}}
]
我如何只选择“$ oid”的值并以下列方式保存json:
"student": [
{
"name": "Xyz",
"college": "abc",
"student_id":
"59a9314f6d0000920962e247"
},
{
"name": "DDD",
"college": "opop",
"student_id":
"59a9314f6d0000920962e257"
}
]
答案 0 :(得分:0)
在我的场景中,我是从客户端读取的 -
String Json = null;
JsonNode body = request().body().asJson();
Json = body.toString();
Logger.info(Json);
String role = body.get("role").get("role").asText();
users.firstName = body.get("firstName").asText();
users.lastName = body.get("lastName").asText();
您需要根据您的方案更改JsonNode body = request().body().asJson();
和其他代码的定义,以便从db中获取它。
答案 1 :(得分:0)
您需要将"student_id"
jsValue替换为字符串值,如下所示:
val original: JsValue = Json.parse(
""" {"student": [
{
"name": "Xyz",
"college": "abc",
"student_id":{
"$oid": "59a9314f6d0000920962e247"
}},
{
"name": "DDD",
"college": "opop",
"student_id":{
"$oid": "59a9314f6d0000920962e257"
}}
]}""")
val changed = original.as[JsObject] ++ Json.obj(
"student" -> Json.arr {
original.transform((__ \ 'student)
.json.pick[JsArray])
.getOrElse(Json.arr())
.value.map(e => {
val value = e.transform((__ \ 'student_id \ '$oid).json.pick[JsString]).get
e.as[JsObject] ++ Json.obj("student_id" -> value)
})
})
println(Json.stringify(changed))
//Result:
{"student":[[{"name":"Xyz","college":"abc","student_id":"59a9314f6d0000920962e247"},{"name":"DDD","college":"opop","student_id":"59a9314f6d0000920962e257"}]]}