Question

我一直试图编写一个函数，它接受变量a和b作为起点和终点，并计算从a到b的距离为0到1之间的分数。（该分数是变量x ）。

我已经部分工作的代码，但它并不总是与负数一起正常工作。例如，如果a = -2和b = -1以及x = 1输出应为-1，但我得-2。

到目前为止，我一直使用if语句解决类似的问题，但我不想继续这样做。有更优雅的解决方案吗？

def interval_point(a, b, x):
        """Given parameters a, b and x. Takes three numbers and interprets a and b
        as the start and end point of an interval, and x as a fraction
        between 0 and 1 that returns how far to go towards b, starting at a"""
        if a == b:
            value = a
        elif a < 0 and b < 0 and x == 0:
            value = a
        elif a < 0 and b < 0:
            a1 = abs(a)
            b1 = abs(b)
            value = -((a1-b1) + ((a1-b1)*x))
        else:
            value = (a + (b-a)*x)
        return(value)

Answer 1

我在数学上玩了一些，我已经找到了解决问题的简单方法。

这就是现在的功能：

def interval_point(a, b, x):
    """Given parameters a, b and x. Takes three numbers and interprets a and b
    as the start and end point of an interval, and x as a fraction
    between 0 and 1 that returns how far to go towards b, starting at a"""
    return((b - a) * x + a)

在python中更有效地编码间隔点计算器

1 个答案: