HTML元素的正确X路径？

Question

我需要抓取这个HTML页面......

http://www1.usl3.toscana.it/default.asp?page=ps&ospedale=3

....使用PHP和XPath在字符串附近获得值 7 ＆＃34; CODICE GIALLO ＆＃34;

（注意：如果您尝试浏览它，您可以在该页面中看到不同的值...它并不重要......它会改变它的恐怖......）

我使用此PHP代码示例来打印值...

<?php
    ini_set('display_errors', 'On');
    error_reporting(E_ALL);

    $url = 'http://www1.usl3.toscana.it/default.asp?page=ps&ospedale=3';

    $xpath_for_parsing = '/html/body/div/div[2]/table[2]/tbody/tr[1]/td/table/tbody/tr[3]/td[2]/table/tbody/tr[4]/td[2]/table/tbody/tr[2]/td[2]/b';

    //#Set CURL parameters: pay attention to the PROXY config !!!!
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_AUTOREFERER, TRUE);
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE);
    curl_setopt($ch, CURLOPT_PROXY, '');
    $data = curl_exec($ch);
    curl_close($ch);

    $dom = new DOMDocument();
    @$dom->loadHTML($data);

    $xpath = new DOMXPath($dom);

    $colorWaitingNumber = $xpath->query($xpath_for_parsing);
    $theValue =  'N.D.';
    foreach( $colorWaitingNumber as $node )
    {
      $theValue = $node->nodeValue;
    }

    print $theValue;
?>

通过这种方式，我获得了＆＃34; N.D。＆＃34;输出不是＆＃34; 7 ＆＃34;正如我想的那样。

阅读此Why does my XPath query (scraping HTML tables) only work in Firebug, but not the application I'm developing?我发现该问题与<tbody>标记有关，因此我尝试将其从原始xpath中删除，并尝试使用以下代码：

$xpath_for_parsing = '/html/body/div/div[2]/table[2]/tr[1]/td/table/tr[3]/td[2]/table/tr[4]/td[2]/table/tr[2]/td[2]/b'

但结果仍然是＆＃34; N.D。＆＃34;而不是＆＃34; 7 ＆＃34;。

使用

$xpath_for_parsing = '/html/body/div/div[2]/table[2]/tr[1]/td/table/tr[3]/td[2]/table/tr[4]/td[2]/table'

结果是＆＃34; Codice GIALLO 7 ＆＃34;

我如何才能获得＆＃34; 7 ＆＃34;值？

任何建议/示例？

Answer 1

这个应该可以解决问题：

//td[.="Codice GIALLO"]/following-sibling::td/b