如何在Google地图中的两个坐标点之间绘制一个圆弧,就像在此图像中一样,像iOS中的facebook post一样?
答案 0 :(得分:5)
在使用以下功能之前,请不要忘记导入 GoogleMaps 积分:xomena
func drawArcPolyline(startLocation: CLLocationCoordinate2D?, endLocation: CLLocationCoordinate2D?) {
if let _ = startLocation, let _ = endLocation {
//swap the startLocation & endLocation if you want to reverse the direction of polyline arc formed.
let mapView = GMSMapView()
let path = GMSMutablePath()
path.add(startLocation!)
path.add(endLocation!)
// Curve Line
let k: Double = 0.2 //try between 0.5 to 0.2 for better results that suits you
let d = GMSGeometryDistance(startLocation!, endLocation!)
let h = GMSGeometryHeading(startLocation!, endLocation!)
//Midpoint position
let p = GMSGeometryOffset(startLocation!, d * 0.5, h)
//Apply some mathematics to calculate position of the circle center
let x = (1-k*k)*d*0.5/(2*k);
let r = (1+k*k)*d*0.5/(2*k);
let c = GMSGeometryOffset(p, x, h + 90.0)
//Polyline options
//Calculate heading between circle center and two points
let h1 = GMSGeometryHeading(c, startLocation!)
let h2 = GMSGeometryHeading(c, endLocation!)
//Calculate positions of points on circle border and add them to polyline options
let numpoints = 100.0
let step = ((h2 - h1) / Double(numpoints))
for i in stride(from: 0.0, to: numpoints, by: 1) {
let pi = GMSGeometryOffset(c, r, h1 + i * step)
path.add(pi)
}
//Draw polyline
let polyline = GMSPolyline(path: path)
polyline.map = mapView // Assign GMSMapView as map
polyline.strokeWidth = 3.0
let styles = [GMSStrokeStyle.solidColor(UIColor.black), GMSStrokeStyle.solidColor(UIColor.clear)]
let lengths = [20, 20] // Play with this for dotted line
polyline.spans = GMSStyleSpans(polyline.path!, styles, lengths as [NSNumber], .rhumb)
let bounds = GMSCoordinateBounds(coordinate: startLocation!, coordinate: endLocation!)
let insets = UIEdgeInsets(top: 20, left: 20, bottom: 20, right: 20)
let camera = mapView.camera(for: bounds, insets: insets)!
mapView.animate(to: camera)
}
}
答案 1 :(得分:1)
我用Bezier二次方程画曲线。 You can have a look on to the implementation。这是示例代码。
func bezierPath(from startLocation: CLLocationCoordinate2D, to endLocation: CLLocationCoordinate2D) -> GMSMutablePath {
let distance = GMSGeometryDistance(startLocation, endLocation)
let midPoint = GMSGeometryInterpolate(startLocation, endLocation, 0.5)
let midToStartLocHeading = GMSGeometryHeading(midPoint, startLocation)
let controlPointAngle = 360.0 - (90.0 - midToStartLocHeading)
let controlPoint = GMSGeometryOffset(midPoint, distance / 2.0 , controlPointAngle)
let path = GMSMutablePath()
let stepper = 0.05
let range = stride(from: 0.0, through: 1.0, by: stepper)// t = [0,1]
func calculatePoint(when t: Double) -> CLLocationCoordinate2D {
let t1 = (1.0 - t)
let latitude = t1 * t1 * startLocation.latitude + 2 * t1 * t * controlPoint.latitude + t * t * endLocation.latitude
let longitude = t1 * t1 * startLocation.longitude + 2 * t1 * t * controlPoint.longitude + t * t * endLocation.longitude
let point = CLLocationCoordinate2D(latitude: latitude, longitude: longitude)
return point
}
range.map { calculatePoint(when: $0) }.forEach { path.add($0) }
return path
}
答案 2 :(得分:0)
Objective-C版本@Rouny答案
check5, check8, check12, check15 : boolean;
radiofivechanged(){
this.check5 = true;
this.check8 = false;
this.check12 = false;
this.check15 = false;
}
答案 3 :(得分:0)
上面的答案并不能解决所有的极端情况,这是一种很好地绘制圆弧的方法:
func drawArcPolyline(startLocation: CLLocationCoordinate2D?, endLocation: CLLocationCoordinate2D?) {
if let _ = startLocation, let _ = endLocation {
//swap the startLocation & endLocation if you want to reverse the direction of polyline arc formed.
var start = startLocation!
var end = endLocation!
var gradientColors = GMSStrokeStyle.gradient(
from: UIColor(red: 11.0/255, green: 211.0/255, blue: 200.0/255, alpha: 1),
to: UIColor(red: 0/255, green: 44.0/255, blue: 66.0/255, alpha: 1))
if startLocation!.heading(to: endLocation!) < 0.0 {
// need to reverse the start and end, and reverse the color
start = endLocation!
end = startLocation!
gradientColors = GMSStrokeStyle.gradient(
from: UIColor(red: 0/255, green: 44.0/255, blue: 66.0/255, alpha: 1),
to: UIColor(red: 11.0/255, green: 211.0/255, blue: 200.0/255, alpha: 1))
}
let path = GMSMutablePath()
// Curve Line
let k = abs(0.3 * sin((start.heading(to: end)).degreesToRadians)) // was 0.3
let d = GMSGeometryDistance(start, end)
let h = GMSGeometryHeading(start, end)
//Midpoint position
let p = GMSGeometryOffset(start, d * 0.5, h)
//Apply some mathematics to calculate position of the circle center
let x = (1-k*k)*d*0.5/(2*k);
let r = (1+k*k)*d*0.5/(2*k);
let c = GMSGeometryOffset(p, x, h + 90.0)
//Polyline options
//Calculate heading between circle center and two points
var h1 = GMSGeometryHeading(c, start)
var h2 = GMSGeometryHeading(c, end)
if(h1>180){
h1 = h1 - 360
}
if(h2>180){
h2 = h2 - 360
}
//Calculate positions of points on circle border and add them to polyline options
let numpoints = 100.0
let step = (h2 - h1) / numpoints
for i in stride(from: 0.0, to: numpoints, by: 1) {
let pi = GMSGeometryOffset(c, r, h1 + i * step)
path.add(pi)
}
path.add(end)
//Draw polyline
let polyline = GMSPolyline(path: path)
polyline.map = mapView // Assign GMSMapView as map
polyline.strokeWidth = 5.0
polyline.spans = [GMSStyleSpan(style: gradientColors)]
}
}
答案 4 :(得分:0)
提到的答案中没有一个是完整的解决方案。对于一些位置,它绘制一个圆而不是一条折线。 为了解决这个问题,我们将计算方位角(从真北开始的顺时针方向度数),如果小于零,请交换起点和终点位置。
func createArc(
startLocation: CLLocationCoordinate2D,
endLocation: CLLocationCoordinate2D) -> GMSPolyline {
var start = startLocation
var end = endLocation
if start.bearing(to: end) < 0.0 {
start = endLocation
end = startLocation
}
let angle = start.bearing(to: end) * Double.pi / 180.0
let k = abs(0.3 * sin(angle))
let path = GMSMutablePath()
let d = GMSGeometryDistance(start, end)
let h = GMSGeometryHeading(start, end)
let p = GMSGeometryOffset(start, d * 0.5, h)
let x = (1 - k * k) * d * 0.5 / (2 * k)
let r = (1 + k * k) * d * 0.5 / (2 * k)
let c = GMSGeometryOffset(p, x, h + 90.0)
var h1 = GMSGeometryHeading(c, start)
var h2 = GMSGeometryHeading(c, end)
if (h1 > 180) {
h1 = h1 - 360
}
if (h2 > 180) {
h2 = h2 - 360
}
let numpoints = 100.0
let step = ((h2 - h1) / Double(numpoints))
for i in stride(from: 0.0, to: numpoints, by: 1) {
let pi = GMSGeometryOffset(c, r, h1 + i * step)
path.add(pi)
}
path.add(end)
let polyline = GMSPolyline(path: path)
polyline.strokeWidth = 3.0
polyline.spans = GMSStyleSpans(
polyline.path!,
[GMSStrokeStyle.solidColor(UIColor(hex: "#2962ff"))],
[20, 20], .rhumb
)
return polyline
}
方位角是地图上垂直线指向的方向,以北为准,以顺时针为单位。
func bearing(to point: CLLocationCoordinate2D) -> Double {
func degreesToRadians(_ degrees: Double) -> Double { return degrees * Double.pi / 180.0 }
func radiansToDegrees(_ radians: Double) -> Double { return radians * 180.0 / Double.pi }
let lat1 = degreesToRadians(latitude)
let lon1 = degreesToRadians(longitude)
let lat2 = degreesToRadians(point.latitude);
let lon2 = degreesToRadians(point.longitude);
let dLon = lon2 - lon1;
let y = sin(dLon) * cos(lat2);
let x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon);
let radiansBearing = atan2(y, x);
return radiansToDegrees(radiansBearing)
}
答案 5 :(得分:0)
斯威夫特 5+
非常简单流畅的方式
//MARK: - Usage
let path = self.bezierPath(from: CLLocationCoordinate2D(latitude: kLatitude, longitude: kLongtitude), to: CLLocationCoordinate2D(latitude: self.restaurantLat, longitude: self.restaurantLong))
let polyline = GMSPolyline(path: path)
polyline.strokeWidth = 5.0
polyline.strokeColor = appClr
polyline.map = self.googleMapView // Google MapView
简单的功能
func drawArcPolyline(from startLocation: CLLocationCoordinate2D, to endLocation: CLLocationCoordinate2D) -> GMSMutablePath {
let distance = GMSGeometryDistance(startLocation, endLocation)
let midPoint = GMSGeometryInterpolate(startLocation, endLocation, 0.5)
let midToStartLocHeading = GMSGeometryHeading(midPoint, startLocation)
let controlPointAngle = 360.0 - (90.0 - midToStartLocHeading)
let controlPoint = GMSGeometryOffset(midPoint, distance / 2.0 , controlPointAngle)
let path = GMSMutablePath()
let stepper = 0.05
let range = stride(from: 0.0, through: 1.0, by: stepper)// t = [0,1]
func calculatePoint(when t: Double) -> CLLocationCoordinate2D {
let t1 = (1.0 - t)
let latitude = t1 * t1 * startLocation.latitude + 2 * t1 * t * controlPoint.latitude + t * t * endLocation.latitude
let longitude = t1 * t1 * startLocation.longitude + 2 * t1 * t * controlPoint.longitude + t * t * endLocation.longitude
let point = CLLocationCoordinate2D(latitude: latitude, longitude: longitude)
return point
}
range.map { calculatePoint(when: $0) }.forEach { path.add($0) }
return path
}