Question

我是java的新手，我有以下代码，是否有一种使用java8编写它的有效方法：

List<String> apps = new ArrayList<>();

for (ApplicationSummary applicationSummary : appSumList) {
    apps.add(appList.getName());
}

return apps;

Answer 1

appSumList
  .stream()
  .map(ApplicationSummary::getName)
  .collect(Collectors.toList());

Answer 2

是的，假设您要将name个对象的所有ApplicationSummary属性添加到apps List。

类似的东西：

apps
    // adding all to "apps"
    .addAll(
        // streaming list of "ApplicationSummary" items
        appSumList.stream()
        // mapping item to its name
        .map(ApplicationSummary::getName)
        // collecting as List (which is what will be passed to addAll)
        .collect(Collectors.toList()
    )
);`

修改

正如Juan Carlos指出的那样，如果仅想要包含{{}}，则可能不需要在addAll apps上调用List {1}}每个name元素的属性：

appSumList

写入数组速记的条目

2 个答案: