Question

我正在开发一个小程序，尝试使用DataTemplate跟踪MVVM方法，为我的VM创建视图。我遇到的问题是，不是创建视图的实例，而是显示VM的ToString（）结果。如果我在View类（MainNavigation.xaml）的构造函数上放置一个断点，它永远不会到达。

以下代码，非常感谢。

MainWindow.xaml

<Window x:Class="Tester.Wpf.MainWindow"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    xmlns:local="clr-namespace:Tester.Wpf"
    xmlns:scr="clr-namespace:Tester.Wpf.Screens"
    mc:Ignorable="d"
    Title="MainWindow" Height="350" Width="525">

<Window.Resources>
    <DataTemplate DataType="x:Type scr:MainNavigationViewModel">
        <scr:MainNavigation />
    </DataTemplate>
</Window.Resources>

<Grid>
    <ContentControl Name="MainNav" Content="{Binding MainNavigationViewModel2}" />
</Grid>
</Window>

MainWindow.xaml.cs

using System.ComponentModel;
using System.Windows;
using Tester.Wpf.Screens;

namespace Tester.Wpf
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window, INotifyPropertyChanged
    {
        private MainNavigationViewModel _mainNavigationViewModel;

        public MainWindow()
        {
            this.DataContext = this;
            this.MainNavigationViewModel2 = new MainNavigationViewModel();

            InitializeComponent();
        }

        public MainNavigationViewModel MainNavigationViewModel2
        {
            get { return _mainNavigationViewModel; }
            set { _mainNavigationViewModel = value;
                RaisePropertyChangedEvent("MainNavigationViewModel2");
            }
        }

        public event PropertyChangedEventHandler PropertyChanged;

        protected void RaisePropertyChangedEvent(string propertyName)
        {
            PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
        }
    }
}

MainNavigation.xaml.cs

using System.Windows.Controls;

namespace Tester.Wpf.Screens
{
    /// <summary>
    /// Interaction logic for MainNavigation.xaml
    /// </summary>
    public partial class MainNavigation : UserControl
    {
        public MainNavigation()
        {
            InitializeComponent();
        }
    }
}

MainNavigationViewModel.cs

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using Tester.Wpf.Helpers;

namespace Tester.Wpf.Screens
{
    public class MainNavigationViewModel : BaseViewModel
    {
        public int Test = 10;
    }
}

MainNavigation.xaml

<UserControl x:Class="Tester.Wpf.Screens.MainNavigation"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
             xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
             xmlns:local="clr-namespace:Tester.Wpf.Screens"
             mc:Ignorable="d" 
             d:DesignHeight="300" d:DesignWidth="300">

    <Grid Background="Blue">
         <TextBlock>YOU"VE MADE IT!</TextBlock>
    </Grid>
</UserControl>

Answer 1

在MainWindow.xaml文件中，根据Sinatr的评论更改了以下行：

<DataTemplate DataType="x:Type scr:MainNavigationViewModel">

到

<DataTemplate DataType="{x:Type scr:MainNavigationViewModel}">

WPF DataTemplate显示ToString

1 个答案: