Question

我对编码很新，我正在写一本字典，检查我是否知道某些单词的翻译。到目前为止一直很好，但是我有一个小问题，我确信它很简单，但不知道如何改进代码。

当我得到一个正确的单词时，它应该被添加到变量'right'中，但由于它在while循环中，它只执行一次，当我得到另一个单词时，它不会加起来。我该如何解决这个问题？

for key, value in words:
    right = 0
    print ('What does', key, 'mean ?')
    given_meaning = input ('It means: ')
    while True:

        if given_meaning == value:
            right += 1
            x = Decimal(right/dict_len)*100
            final_number = round(x, 2)
            print ('Yes! You got it right!')
            print ('You know', final_number ,'% of the words.')
            break

        if given_meaning != value:
            print ('Unfortunately, this means:', value, '.' )
            print ('You know ', final_number ,'% of the words.')
            break

它不断显示正确的一个词的结果。你能帮忙吗？

Answer 1

right = 0
for key, value in words:
print ('What does', key, 'mean ?')
given_meaning = input ('It means: ')
while True:

    if given_meaning == value:
        right += 1
        x = Decimal(right/dict_len)*100
        final_number = round(x, 2)
        print ('Yes! You got it right!')
        print ('You know', final_number ,'% of the words.')
        break

    if given_meaning != value:
        print ('Unfortunately, this means:', value, '.' )
        print ('You know ', final_number ,'% of the words.')
        break

这应该可以解决问题。你现在拥有它的方式是，你通过for循环每次迭代都设置right = 0。

猜测字的值不会与while循环PYTHON中的指定变量相加

1 个答案: