到目前为止我已经
了def attack(words):
words = ['noun', 'verb', 'adjective', 'place']
print('Use your', words[2], words[0], 'and', words[1], 'towards the', words[3]+'!')
我想输入:
attack([shiny, broom, jump, sky])
所以句子应该是这样的:用闪亮的扫帚跳到天空!
但它正在打印:使用你的形容词名词和动词来到这个地方!
任何想法我错过了什么?
答案 0 :(得分:4)
也许是这样的,根据你需要的单词类型将输入列表编入索引?
def attack(words):
noun, verb, adjective, place = 0, 1, 2, 3
print('Use your', words[adjective], words[noun], 'and', words[verb], 'towards the', words[place]+'!')
答案 1 :(得分:2)
删除words = ["noun", "verb", "adjective", "place"]
。
您接受[shiny, broom, jump, sky]
作为words
函数的attack()
参数,并通过将["noun", "verb", "adjective", "place"]
分配给同名变量来立即覆盖该值。此外,[shiny, broom, jump, sky]
列表的元素缺少引号,除非它们是变量而不是字符串。
您的代码应为:
def attack(words):
print("Use your", words[2], words[0], "and", words[1], "towards the", words[3] + "!")
attack(["shiny", "broom", "jump", "sky"])