基于嵌套对象值

Question

我有一个对象，我想根据它的投票进行排序，然后映射新的/已排序的对象。

const data = {
  "comment-1508872637211" : {
    "description" : "Blah",
    "votes" : 1
  },
  "comment-1508872675949" : {
    "description" : "Question",
    "votes" : 11
  },
  "comment-1508898578089" : {
    "description" : "whatever\n",
    "votes" : 5
  },
  "comment-1508898637092" : {
    "description" : "new",
    "votes" : 15
  },
  "comment-1508900306998" : {
    "description" : "baj",
    "votes" : 0
  }
}

console.log(data);

const sortedOnVotes = Object.entries(data);

console.log(sortedOnVotes);

// This is the part I'm getting hung up on
const newDataObject = sortedOnVotes.map(([key, value]) => value).sort();

console.log(newDataObject)

最终，我希望这个新对象仍然保留评论 - ###密钥，并根据其拥有的投票数量进行过滤。例如，newDataObject应返回如下内容：

const newDataObject = {
          "comment-1508900306998" : {
            "description" : "baj",
            "votes" : 0
          },
          "comment-1508872637211" : {
            "description" : "Blah",
            "votes" : 1
          },
          "comment-1508898578089" : {
            "description" : "whatever\n",
            "votes" : 5
          },
          "comment-1508872675949" : {
            "description" : "Question",
            "votes" : 11
          }
          "comment-1508898637092" : {
            "description" : "new",
            "votes" : 15
          }

}

我认为我使用Object.values或Object.entries走在了正确的轨道上，但我真的很喜欢它。

真的很感激任何帮助，谢谢！

https://codepen.io/MathiasaurusRex/pen/RLzYVV

Answer 1

您可以使用sort()函数编写逻辑来对数组进行排序，如下所示 -

const data = {
  "comment-1508872637211" : {
    "description" : "Blah",
    "votes" : 1
  },
  "comment-1508872675949" : {
    "description" : "Question",
    "votes" : 11
  },
  "comment-1508898578089" : {
    "description" : "whatever\n",
    "votes" : 5
  },
  "comment-1508898637092" : {
    "description" : "new",
    "votes" : 15
  },
  "comment-1508900306998" : {
    "description" : "baj",
    "votes" : 0
  }
}

console.log(data);

const sortedOnVotes = Object.entries(data);

console.log(sortedOnVotes);

var result = sortedOnVotes.sort(function(a,b) {
  return a[1].votes - b[1].votes;
});

console.log(result);