我有两个功能匹配,并且总工作正常。我希望函数total project match将第一个函数除以第二个函数乘以100。最后一个函数不起作用!
到目前为止,这是我的代码:
matchContribution.subscribe(function (newValue) {
if (newValue != undefined && newValue != '') {
matchContribution(formatInt(newValue));
var dataValue = Number(matchContribution().replace(/\,/g, ''));
if (dataValue > 999999999999.99 || dataValue < 0) {
matchContribution('');
}
if (loading == false) {
sendCommand('SAVE');
}
}
});
var totalProjectCost = ko.computed(function () {
var total = 0;
var hasUserInput = false;
if (grantRequest() != '' && grantRequest() != undefined) {
hasUserInput = true;
total = total + Number(String(grantRequest()).replace(/\,/g, ''));
}
if (matchContribution() != '' && matchContribution() != undefined) {
hasUserInput = true;
total = total + Number(String(matchContribution()).replace(/\,/g, ''));
}
if (total == 0) {
if (!hasUserInput)
return '';
else
return formatInt('0');
}
else {
if (loading == false) {
sendCommand('SAVE');
}
return formatInt(total);
}
});
var totalProjectMatch = matchContribution()/totalProjectCost();
if(totalProjectMatch>=0)
totalProjectMatch = Math.floor(totalProjectMatch);
else
totalProjectMatch = Math.ceil(totalProjectMatch);
答案 0 :(得分:0)
var totalProjectMatch = ko.computed(function () {
var total = 0;
var hasUserInput = false;
if ((grantRequest() != '' && grantRequest() != undefined) && (matchContribution() != '' && matchContribution() != undefined) && (totalProjectCost() != '' && totalProjectCost() != undefined)) {
hasUserInput = true;
total = Number(String(matchContribution()).replace(/\,/g, '')) / Number(String(totalProjectCost()).replace(/\,/g, ''));
total = total * 100;
}
if (total == 0) {
if (!hasUserInput)
return '';
else
return formatInt('0');
}
else {
if (loading == false) {
sendCommand('SAVE');
}
return formatNumber(total);
}
});
我解决了这个问题!非常感谢!希望能帮助别人。