Question

我试图找到一张包含4个表格的表格：clients，groups_clients，client_data1，client_data2;

客户端

clId| GroupId  | Other |
------------------------
 1  | 1        | gddgdg|
 2  | 1        | dgdg  |
 3  | 2        | ddg   |
 4  | 2        | dd4g  |
 5  | 1        | ddg   |

groups_clients

 grId | GroupName| 
 -----------------
   1  | Group1   |
   2  | Group2   |

table_data1

 clId | Date       | Buy  | Trade |
  --------------------------------
   1  | 2017-06-05 | 3    | 4     |
   2  | 2017-11-10 | 6    | 9     |
   2  | 2017-11-11 | 4    | 13    | 
   2  | 2017-03-01 | 11   | 0     |  
   4  | 2017-01-10 | 3    | 11    |

table_data2

 clId | Date       | With | Depos |
  --------------------------------
   1  | 2017-03-05 | 1    | 3     |
   5  | 2017-08-10 | 0    | 8     |
   2  | 2017-11-11 | 0    | 13    | 
   3  | 2017-03-01 | 11   | 0     |  
   4  | 2017-01-10 | 3    | 11    |

理想的表应该是这样的

GroupName | SUM(Buy) | SUM(Trade) | SUM(With) | SUM(Depos) |
------------------------------------------------------------
  Group1  | 13       | 26         | 1         | 24         |
  Group2  | 3        | 11         | 14        | 11         |

查询应该汇总从table_data1获取的所有行以及table_data2，其中日期为some date并将其分组为group name

这是我的代码：

SELECT 
    groups_clients.GroupName as group_name, 
    clients.GroupId AS groupid, 
    SUM(table_data1.buy) AS buy, 
    SUM(table_data1.trade) AS trade, 
    with,
    depos
FROM 
    table_data1 
INNER JOIN 
    (SELECT 
         SUM(table_data2.with) AS with, 
         clients.clId, GroupId 
     FROM 
         clients 
     LEFT JOIN 
         table_data2 ON clients.clId = table_data2.clId 
                     AND table_data2.date <= '11-11-2016' 
     GROUP BY 
         GroupId, clId) clients ON table_data1.clId = clients.clId 
LEFT JOIN 
    groups_clients ON groups_clients.Id = clients.GroupId 
WHERE 
    table_data1.date <= '11-11-2016'
GROUP BY 
    clients.GroupId, With, Depos, 
    groups_clients.GroupName

但结果有点可怕。它连续输出了很多相同的组，好像我没有按groupname分组。伙计们，我需要你的帮助。有任何想法吗？我该怎么做才能使查询工作正常？提前谢谢！

Answer 1

您必须预先对SUMS进行分组，然后加入以避免重复计算行。

DECLARE @mydate DATETIME
SELECT @mydate='11/11/2017'

SELECT gc.GroupName, 
        isnull(SUM([Buy]), 0) [Buy], 
        isnull(SUM([Trade]), 0) [Trade], 
        isnull(SUM([With]), 0) [With], 
        isnull(SUM([Depos]), 0) [Depos]
FROM groups_clients gc
    INNER JOIN clients c ON gc.grId=c.GroupId
    LEFT JOIN (SELECT clId, SUM([Buy]) [Buy], SUM([Trade])[Trade]
        FROM table_data1 WHERE [Date]=@mydate GROUP BY clId) a ON c.clId=a.clId
    LEFT JOIN (SELECT clId, SUM([With]) [With], SUM([Depos])[Depos] 
        FROM table_data2 WHERE [Date]=@mydate GROUP BY clId) b ON c.clId=b.clId
GROUP BY gc.GroupName

Answer 2

您是否尝试过从group_client表开始..加入到客户端，然后加入table_data1和table_data2 ..然后聚合您想要的列？

所以查询会像这样

declare @date date = '2017-06-05'

select 

gc.groupname 
,sum(td1.buy) as total_buy
,sum(td1.Trade) as total_trade
,sum(td2.with) as total_with
,sum(td2.Depos) as total_depos

from groups_client gc

    inner join clients c
        on c.groupid = gc.grid

    inner join table_data1 td1
        on td1.clid = c.clid
        and td1.Date = @date

    inner join table_data2 td2
        on td2.clid = c.clid
        and td2.Date = @date

        group by 

        gc.groupname

如何使用子查询SQL组合4个表？

2 个答案: