Question

所以我根据一张表撤回不同的account_ids，然后加入第二张表来汇总所述帐户的所有发票。

EX：account_id：1234567

假设有4张发票与1234567相关联，我正在总结这4张发票的数量并将其反映出去。

现在，我还想循环查看这4张发票，并检查其中的任何一张是否属于原始表格承诺中我'日期'后的90天内。

这是我所拥有的，但它不起作用，因为这只是抓取最近的发票，而我需要遍历所有这些以检查它是否为“新”（90天内没有发票）或' RECURRING'（这4张发票中的任何一张都在90天内）

这是我目前的代码：

SELECT  
    MIN(c.created_at) AS date,
    c.meta_account_Id, 
    c.organization_Id, 
    c.user_id, 
    c.meta_distributorId, 
    c.meta_accountName,
    sum( CASE WHEN s.invoice_date>=c.created_at 
         THEN  coalesce(s.volumece,0)     
         ELSE 0
         END ) AS ces,
    CASE WHEN (max(s.invoice_date)) BETWEEN (adddays(MIN(c.created_at),-90)) AND (adddays(MIN(c.created_at),1)) 
         THEN 'RECURRING'
         ELSE 'NEW'
         END AS type

FROM [commitments] c

LEFT JOIN [Sales2] s ON c.organization_Id=s.org_id AND
                        c.meta_account_Id=s.account_id

WHERE 
      c.status='active' AND 
      c.organization_Id='57aa010ae6125c0b007d241c' AND 
      c.user_id='598de688834ff20518a536d9'


GROUP BY 
      c.meta_account_Id, 
      c.organization_Id, 
      c.user_id, 
      c.meta_distributorId, 
      c.meta_accountName

Answer 1

我接受它而不是知道MAX invoiceDate是否在90天内，这是：

CASE
    WHEN (max(s.invoice_date)) BETWEEN 
(adddays(MIN(c.created_at),-90)) AND (adddays(MIN(c.created_at),1)) 
THEN 'RECURRING'
    ELSE 'NEW'
END AS type

您想要返回＆＃34; RECURRING＆＃34;如果任何相关的invoiceDate在90天内。这样做的方法（至少在我所知道的所有SQL版本中）都是使用EXISTS（）函数：

CASE
    WHEN EXISTS(SELECT * FROM Sales2 t1
WHERE t1.invoice_date BETWEEN 
(adddays(MIN(c.created_at),-90)) AND (adddays(MIN(c.created_at),1)) 
AND c.organization_Id=t1.org_id AND 
    c.meta_account_Id=t1.account_id)
THEN 'RECURRING'
    ELSE 'NEW'
END AS type

如果在此范围内的SQL，则为true，否则为false

1 个答案: