Question

我正在为我的同事开发一个GUI界面，我想在用户选中复选框时添加一个带复选框的ListView和“make stuff”。

我在StackOverflow和Technet上做了很多搜索，到目前为止，我只有一些我可以设置（带有绑定）的复选框，但是我无法在支票上创建或捕获任何事件事件

我做了一个小的GUI界面来进行试验和错误。所以我的XAML代码如下所示：

<Window
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
    xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
    xmlns:local="clr-namespace:GUI_Techgenix"
    mc:Ignorable="d"
    Title="Powershell GUI Training" Height="250" Width="400">
    <Grid>
        <ListView x:Name="listSort" HorizontalAlignment="Left" Height="132" Margin="15,15,0,0" VerticalAlignment="Top" Width="350">
            <ListView.View>
                <GridView AllowsColumnReorder="true" ColumnHeaderToolTip="InfoPaquet">
                    <GridViewColumn Header="Play">
                        <GridViewColumn.CellTemplate>
                            <DataTemplate>
                                <CheckBox IsChecked="{Binding Play}"/>
                            </DataTemplate>
                        </GridViewColumn.CellTemplate>
                    </GridViewColumn>
                    <GridViewColumn DisplayMemberBinding="{Binding Path=PkgName}">
                        <GridViewColumnHeader>Package Name</GridViewColumnHeader>
                    </GridViewColumn>
                    <GridViewColumn DisplayMemberBinding="{Binding Path=ProgramName}">
                        <GridViewColumnHeader>Program Name</GridViewColumnHeader>
                    </GridViewColumn>
                    <GridViewColumn DisplayMemberBinding="{Binding Path=SequenceID}">
                        <GridViewColumnHeader>SequenceID</GridViewColumnHeader>
                    </GridViewColumn>
                </GridView>
            </ListView.View>
        </ListView>
    </Grid>
</Window>

我的Powershell代码如下所示：

Set-Location $PSScriptRoot
#Loading modules
#Module to import XAML inspire by these nice walkthrough :
    - https://foxdeploy.com/2015/04/16/part-ii-deploying-powershell-guis-in-minutes-using-visual-studio/
    - http://techgenix.com/building-powershell-gui-part2/
Import-Module .\XAML-Loader -ErrorAction Stop

$mainWindow = Open-XamlForm(".\FormTest.xaml")

$testobj = New-Object -TypeName PSObject
$testobj | Add-Member -MemberType NoteProperty -Name ("PkgName") -Value "Test"
$testobj | Add-Member -MemberType NoteProperty -Name ("ProgramName") -Value "Install"
$testobj | Add-Member -MemberType NoteProperty -Name ("Play") -Value "True"
$mainWindow.listSort.AddChild($testobj)

$testobj2 = New-Object -TypeName PSObject
$testobj2 | Add-Member -MemberType NoteProperty -Name ("PkgName") -Value "Test2"
$testobj2 | Add-Member -MemberType NoteProperty -Name ("ProgramName") -Value "Install Notes"
$testobj2 | Add-Member -MemberType NoteProperty -Name ("Play") -Value "False"
$mainWindow.listSort.AddChild($testobj2)

$mainWindow.listSort.add_MouseLeftButtonUp({
    Write-host "ClickThatUp!"
})

$mainWindow.XamGUI.ShowDialog() | Out-Null

add_MouseLeftButtonUp在列表视图中的任何位置都很有用，除了复选框。

Answer 1

如果您真的想要XAML UI，则此答案不适用。就个人而言，我从不尝试在PowerShell中编写GUI ...

您考虑过Out-GridView吗？

$data = @(
[PSCustomObject]@{Name='Name1'; Description='Description1'}
[PSCustomObject]@{Name='Name2'; Description='Description2'}
[PSCustomObject]@{Name='Name3'; Description='Description3'}
)
$data | Out-GridView -Title MyTitle -OutputMode Multiple

从ListView捕获Checkbox事件

1 个答案: