Question

我需要检查一个纪元时间是否少于1天，3天和5天。这似乎有效，但对于python来说感觉过于复杂。可以简化吗？

import datetime
feed_time = 1508522102
d1 = round((datetime.datetime.now() - datetime.timedelta(1)).timestamp())
d2 = round((datetime.datetime.now() - datetime.timedelta(3)).timestamp())
d3 = round((datetime.datetime.now() - datetime.timedelta(5)).timestamp())
if feed_time > d1:
    print("less than one day")
    # do something if feed_time is less than 1 day
if feed_time > d2:
    print("less than three days")
    # do something if feed_time is less than 3 days
if feed_time > d3:
    print("less than five days")
    # do something if feed_time is less than 5 days

Answer 1

不确定;将时间延迟列入清单;使用索引遍历列表。找到正确的输出级别后，从另一个列表中打印相应的消息。

check = [datetime.timedelta(1)).timestamp(),
         datetime.timedelta(3)).timestamp(),
         datetime.timedelta(5)).timestamp()]

message = ["one day", "three days", "five days"]

for day in range(3):
    if feed_time > round(datetime.datetime.now() - check[day]):
        print message[day]
        break

那样的东西？

Answer 2

您只需time.now() - feed_time并将其与x*24*60*60进行比较。

如果您想考虑DST，则会更复杂。

Python 3，检查纪元时间是否在时间范围内

2 个答案: