Question

抱歉笨拙的格式化。我写了这个回文检查程序，无法弄清楚为什么它总是返回true。＆＃39;单词＆＃39;指的是通过html的摄取，并且报告ifIfPalindrome＆＃39;。值被吸收并显示，因此html没有问题。任何帮助表示赞赏

const wordBox = document.getElementById('word');

wordBox.addEventListener('input', checkIfPalindrome);

function checkIfPalindrome() {

    const word = wordBox.value;
    const allCaps = word === word.toUpperCase();
    const outsideTrim = allCaps === word.trim();
    let completelyTrimmed = "";
    let individualCharacter = "";

    for(x=0; x<outsideTrim.length; x++)
    {
        individualCharacter = outsideTrim.substring(x, x+1)
        completelyTrimmed+= individualCharacter === " "? "": individualCharacter;
    }

    let reverseString = ""
    for (x=completelyTrimmed.length-1; x>=0; x--){
        reverseString = completelyTrimmed.substring(x, x+1);
    }   

    let result = completelyTrimmed===reverseString;
    document.getElementById('reportIfPalindrome').innerHTML = result;

}

Answer 1

您的代码中存在相当多的缺陷。首先，您正在为您看似打算存储大写和修剪单词的变量存储布尔值。其次，您没有使用正确的边界条件运行循环。请参阅下面的更新代码段。

＆＃13;

checkIfPalindrome();
function checkIfPalindrome() {

    const word = "aBa";
    const allCaps = word.toUpperCase();
    const outsideTrim = allCaps.trim();
    let completelyTrimmed = "";
    let individualCharacter = "";

    for(x=0; x<outsideTrim.length; x++)
    {
        individualCharacter = outsideTrim.substring(x, x+1)
        completelyTrimmed+= individualCharacter === " "? "": individualCharacter;
    }

    let reverseString = ""
    for (x=completelyTrimmed.length-1; x>=0; x--){
        reverseString = reverseString + completelyTrimmed.substring(x, x+1);
    }   

    let result = completelyTrimmed===reverseString;
    //document.getElementById('reportIfPalindrome').innerHTML = result;
    console.log(result);

}

＆＃13;

检查Palindrome程序是否始终返回True

1 个答案: