我已经从数据框创建了一个excel文件,如下所示:
In [215]: import pandas as pd
In [216]: df = pd.DataFrame({"Name": ["A", "B", "C"], "Status": ['y', 'n', 'yy']})
In [217]: df
Out[217]:
Name Status
0 A y
1 B n
2 C yy
如何根据bg_color
的值为“名称”设置Status
?我尝试了几个选项没有成功:
format1 = workbook.add_format({"bg_color": "#669731"})
format2 = workbook.add_format({"bg_color": "#FFFA22"})
format3 = workbook.add_format({"bg_color": "#A43829"})
选项1
worksheet.conditional_format("A2",
{"type": "formula",
"criteria": "=ISNUMBER(SEARCH('y', B2))",
"format": format1
}
)
选项2
worksheet.conditional_format("A2",
{"type": "formula",
"criteria": "=$B$2='y'",
"format": format1
}
)
这些都没有给出预期的结果,当我打开文件时,出现以下消息时出现错误: .xlsx中不可读的内容
如果我能以某种方式设置这样做而不迭代数据帧的值,那将是很好的。
答案 0 :(得分:4)
Excel似乎不喜欢字符串上条件格式的单引号。如果内部有双引号,即
,则有效"criteria": '=($B$2="y")'
与
"criteria": "=($B$2='y')"
我已经在下面提供了一个完整的可重现的示例,其中包含解决方案的屏幕截图。
import pandas as pd
df = pd.DataFrame({"Name": ["A", "B", "C"], "Status": ['y', 'n', 'yy']})
writer = pd.ExcelWriter('test.xlsx', engine='xlsxwriter')
df.to_excel(writer, sheet_name='Sheet1', index=False)
workbook = writer.book
worksheet = writer.sheets['Sheet1']
format1 = workbook.add_format({"bg_color": "#669731"})
worksheet.conditional_format("A2",
{"type": "formula",
"criteria": '=($B$2="y")',
"format": format1
}
)
workbook.close()
如果要为列中的1000个单元格设置此条件格式,则可以使用条件格式的代码。
worksheet.conditional_format("A2:A1001",
{"type": "formula",
"criteria": '=(B2:B1001="y")',
"format": format1
}
)
另一方面,如果你想在一个范围内设置多个条件,我认为这是可能的唯一方法是使用for循环,用匹配条件的格式写每个单元格。我已经提供了下面的例子以及它的预期输出。请注意,如果它满足三个条件中的任何一个条件,它会覆盖已放入单元格中的内容,这有点作弊。
import pandas as pd
df = pd.DataFrame({"Name": ["A", "B", "C"], "Status": ['y', 'n', 'yy']})
writer = pd.ExcelWriter('test.xlsx', engine='xlsxwriter')
df.to_excel(writer, sheet_name='Sheet1', index=False)
workbook = writer.book
worksheet = writer.sheets['Sheet1']
format1 = workbook.add_format({"bg_color": "#669731"})
format2 = workbook.add_format({"bg_color": "#FFFA22"})
format3 = workbook.add_format({"bg_color": "#A43829"})
for i in range (0, len(df)):
if df['Status'].ix[i] == "y":
worksheet.write(i+1, 0, df['Name'].ix[i], format1)
elif df['Status'].ix[i] == "n":
worksheet.write(i+1, 0, df['Name'].ix[i], format2)
elif df['Status'].ix[i] == "yy":
worksheet.write(i+1, 0, df['Name'].ix[i], format3)
workbook.close()