Question

我正在尝试使用Django内置类UpdateView来更新图像模型

模型是：

def get_image_path(instance, filename):
 return '/'.join(['studyoffer_images', instance.study_offer.slug, filename])


class UploadStudyOffer(models.Model):

    study_offer = models.ForeignKey(StudiesOffert, related_name='uploadsstudyoffer')

    image = models.ImageField(upload_to=get_image_path, verbose_name='Seleccionar imagen')
    # images folder per object

    featured = models.BooleanField(default=False, verbose_name='Destacada',
                                   help_text='Indica si la imagen aparecera en el carrusel')
    thumbnail = models.BooleanField(default=False)

    active = models.BooleanField(default=True, verbose_name='Activa',
                                 help_text='Indica si una imagen de oferta esta habilitada o disponible')

    objects = UploadStudyOfferManager()

    def __str__(self):
        return self.study_offer.ad_title

此模型的形式为：

class StudyOfferImagesUploadForm(forms.ModelForm):
    class Meta:
        model = UploadStudyOffer
        fields = ('image', 'active', 'featured')

我现在想要的是允许用户编辑图片并进行更改并更改状态图像（featured，active，thumbnail）

然后我构建我的StudyOfferImageUpdateView来更新图像属性：

class StudyOfferImageUpdateView(SuccessMessageMixin, UserProfileDataMixin, LoginRequiredMixin, UpdateView):
    model = UploadStudyOffer
    form_class = StudyOfferImagesUploadForm
    success_url = reverse_lazy("host:edit-study-offer-image", pk_url_kwarg='pk')
    success_message = "Imagen actualizada"

    def get_context_data(self, **kwargs):
        context = super(StudyOfferImageUpdateView, self).get_context_data(**kwargs)

        user = self.request.user
        return context

    def get_object(self):
        return get_object_or_404(UploadStudyOffer, pk=self.kwargs.get('pk'))

访问此视图的URL是：

url(r"^study-offer/edit/images/(?P<pk>\d+)/$",
        StudyOfferImageUpdateView.as_view(),
        name='edit-study-offer-image'
    ),

当我想编辑我的图像时，模板是这样的：

{% block body_content %}

<h2>Editar imágen</h2>
<form role="form" action="" method="POST" enctype="multipart/form-data">
    {% csrf_token %}
    {{ form.as_p }}
          <input type="submit" value="Update" class="submit-button"> 
</form>
{% endblock %}

此模板已正确重新设置，但是当我按下Update提交按钮时，出现此错误：

Exception Type: TypeError at /host/study-offer/edit/images/47/
Exception Value: reverse() got an unexpected keyword argument 'pk_url_kwarg'

存在此错误，因为在我的StudyOfferImageUpdateView中，Django不接受success_url = reverse_lazy("host:edit-study-offer-image", pk_url_kwarg='pk')

我尝试在pk_url_kwarg='pk'

中打印StudyOfferImageUpdateView句子

q=pk_url_kwarg='pk'
    print(q)

我通过浏览器输入StudyOfferImageUpdateView时的输出是：

# pk string, is not the pk value
pk
System check identified no issues (0 silenced).
October 24, 2017 - 15:58:55
Django version 1.10.7, using settings 'hostayni.settings.development'
Starting development server at http://127.0.0.1:8000/
Quit the server with CONTROL-C.
[24/Oct/2017 15:58:57] "GET /host/study-offer/edit/images/47/ HTTP/1.1" 200 8559

我知道在get_context_data()方法中，pk_url_kwarg='pk'这句话有效，我会在success_url = reverse_lazy("host:edit-study-offer-image", pk_url_kwarg='pk')中传递它并到达字符串pk并且这是我的工作流程被打破的原因。

如何在success_url = reverse_lazy("host:edit-study-offer-image", pk_url_kwarg='pk')中传递预期pk图像的正确参数？

Answer 1

首先，当您致电reverse或reverse_lazy时，您会在args和kwargs中提供参数和关键字参数。你不能pk_url_kwarg='pk'，你需要做kwargs={'pk_url_kwarg': 'pk'}。

但是，您不想在'pk_url_kwarg'字典中使用字符串'pk'和kwargs，您希望使用变量self.pk_url_kwarg和{{1从视图中看。

如果设置self.kwargs['pk']，则无法访问这些变量，因此您需要覆盖success_url。

get_success_url

由于您的观点不打算进行子类化和自定义，因此我认为您根本不需要使用def get_success_url(self): return reverse("host:edit-study-offer-image", kwargs={self.pk_url_kwarg:self.kwargs['pk']})。我会通过硬编码pk_url_kwarg来简化代码。

'pk'

或者改为使用def get_success_url(self): return reverse("host:edit-study-offer-image", kwargs={'pk': self.kwargs['pk']})：

args

reverse（）得到了一个意想不到的关键字参数＆＃39; pk_url_kwarg＆＃39; - UpdateView

1 个答案: