给定这种格式的数组:
[
[{
name: "name",
value: "My-name"
},
{
name: "qty",
value: "1"
},
{
name: "url",
value: "test.com"
},
{
name: "comment",
value: "my-comment"
}
],
[{
name: "name",
value: "My-name2"
},
{
name: "qty",
value: "3"
},
{
name: "url",
value: "test2.com"
}
],
[{
name: "name",
value: "My-name3"
},
{
name: "qty",
value: "1"
},
{
name: "url",
value: "test3.com"
},
{
name: "comment",
value: "my-comment3"
}
]
]
我希望将其切换为:
[
[
{ name: "My-name" },
{ qty: "1" },
{ url: "test.com" },
{ comment: "my-comment", }
],[
{ name: "My-name2" },
{ qty: "3" },
{ url: "test2.com",
],[
{ name: "My-name3", },
{ qty: "1", },
{ url: "test3.com", },
{ comment: "my-comment3", }
]
]
换句话说,交换数组键但保持每个数组元素中的对象结构。
我已尝试在每个元素上循环,并可以使用以下内容交换密钥:
newArray[iCount][item.name] = item.value;
然而,我正努力保留对象顺序。请注意,注释字段可能会也可能不会出现在对象中。
答案 0 :(得分:1)
使用Array.map()
功能:
var arr = [
[{name:"name",value:"My-name"},{name:"qty",value:"1"},{name:"url",value:"test.com"},{name:"comment",value:"my-comment"}],
[{name:"name",value:"My-name2"},{name:"qty",value:"3"},{name:"url",value:"test2.com"}],
[{name:"name",value:"My-name3"},{name:"qty",value:"1"},{name:"url",value:"test3.com"},{name:"comment",value:"my-comment3"}]
],
result = arr.map(function(a){
return a.map(function(obj){
var o = {};
o[obj.name] = obj.value
return o;
});
});
console.log(result);

答案 1 :(得分:1)
检查我的moreBetterOutput
值。我认为会更好。
如果您仍然需要问题中的示例结果,那么您可以检查output
值。
const input = [
[
{
name:"name",
value:"My-name"
},
{
name:"qty",
value:"1"
},
{
name:"url",
value:"test.com"
},
{
name:"comment",
value:"my-comment"
}
],
[
{
name:"name",
value:"My-name2"
},
{
name:"qty",
value:"3"
},
{
name:"url",
value:"test2.com"
}
],
[
{
name:"name",
value:"My-name3"
},
{
name:"qty",
value:"1"
},
{
name:"url",
value:"test3.com"
},
{
name:"comment",
value:"my-comment3"
}
]
]
const output = input.map(arr => arr.map(obj => ({[obj.name]: obj.value})))
const moreBetterOutput = output.map(arr => arr.reduce((acc, item, index) => {
acc[Object.keys(item)[0]] = item[Object.keys(item)[0]];
return acc;
}, {}) )
//console.log(output);
console.log(moreBetterOutput);

答案 2 :(得分:0)
另一个地图功能:
const result = array.map( subarray =>
Object.assign(...subarray.map( ({name, value}) => ({ [name] : value }) ))
);