Question

故事 - 从日志文件中提取信息 - 在本例中是maven构建。基本上我想在首先匹配给定模式后获得与模式匹配的所有行。

换句话说，我希望在[WARNING]行之后匹配以[WARNING] Javadoc Warnings开头的所有行。

我试过用这个：

(?<=\[WARNING\] Javadoc Warnings).*(\r|\n|.)(?=(\[WARNING\].*))

但它只返回下一行。

[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\4

输入

[WARNING] E:\workspaces\asd
[WARNING] E:\workspaces\dsa

[INFO] 
12 warnings
[WARNING] Javadoc Warnings
[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\2
[WARNING] E:\workspaces\3

[INFO] Building jar: E:\workspaces\asdf
[INFO] 
[INFO] >>> maven-source-plugin:3.0.1:j

[INFO] 
[INFO] <<< maven-source-plugin:3.0.1:j
[INFO] 
12 warnings
[WARNING] Javadoc Warnings
[WARNING] E:\workspaces\4
[WARNING] E:\workspaces\5
[WARNING] E:\workspaces\6
[INFO] Building jar: E:\workspaces\asdf
[INFO] 
[INFO] >>> maven-source-plugin:3.0.1:j
[INFO] 
[INFO] <<< maven-source-plugin:3.0.1:j

，所需的结果是

[WARNING] E:\workspaces\1
[WARNING] E:\workspaces\2
[WARNING] E:\workspaces\3
[WARNING] E:\workspaces\4
[WARNING] E:\workspaces\5
[WARNING] E:\workspaces\6

Answer 1

您可以使用以下解决方案：

(?:\G(?!\A)|\[WARNING] Javadoc Warnings)\R(\[WARNING].*)

请参阅regex demo

<强>详情

(?:\G(?!\A)|\[WARNING] Javadoc Warnings) - [WARNING] Javadoc Warnings子字符串（\[WARNING] Javadoc Warnings）或（|）上一次成功匹配的结束（\G(?!\A)）
\R - 换行符
(\[WARNING].*) - 第1组：[WARNING]子字符串及其后的任何0+字符到行尾

请参阅online Java demo：

String s = "[WARNING] E:\\workspaces\\asd\r\n[WARNING] E:\\workspaces\\dsa\r\n\r\n[INFO] \r\n12 warnings\r\n[WARNING] Javadoc Warnings\r\n[WARNING] E:\\workspaces\\1\r\n[WARNING] E:\\workspaces\\2\r\n[WARNING] E:\\workspaces\\3\r\n\r\n[INFO] Building jar: E:\\workspaces\\asdf\r\n[INFO] \r\n[INFO] >>> maven-source-plugin:3.0.1:j\r\n\r\n[INFO] \r\n[INFO] <<< maven-source-plugin:3.0.1:j\r\n[INFO] \r\n12 warnings\r\n[WARNING] Javadoc Warnings\r\n[WARNING] E:\\workspaces\\4\r\n[WARNING] E:\\workspaces\\5\r\n[WARNING] E:\\workspaces\\6\r\n[INFO] Building jar: E:\\workspaces\\asdf\r\n[INFO] \r\n[INFO] >>> maven-source-plugin:3.0.1:j\r\n[INFO] \r\n[INFO] <<< maven-source-plugin:3.0.1:j";
Pattern pattern = Pattern.compile("(?:\\G(?!\\A)|\\[WARNING] Javadoc Warnings)\\R(\\[WARNING].*)");
Matcher matcher = pattern.matcher(s);
while (matcher.find()){
    System.out.println(matcher.group(1)); 
}

匹配后获取前进线，直到线与其他模式匹配

1 个答案: