Question

表：服务

+-----+--------------+
| id  |  title       |
+-----+--------------+
| 1   | Service 1    |
+-----+--------------+
| 2   | Service 2    |
+-----+--------------+

表：研讨会 {HasMany WorkshopServices}

+-----+---------------+
| id  |  title        |
+-----+---------------+
| 1   | Workshop 1    |
+-----+---------------+
| 2   | Workshop 2    |
+-----+---------------+

表： WorkshopServices

+-----+--------------+-------------+
| id  |  workshop_id |  service_id |
+-----+--------------+-------------+
| 1   |  1           |  1          |
+-----+--------------+-------------+
| 2   |  1           |  2          |
+-----+--------------+-------------+

我希望Workshops

找到service_id

我的查询

$this->Workshops->find()
    ->contain([
        'WorkshopServices'
    ])
    ->where([
        'WorkshopServices.service_id IN'=>[1,2,3]
    ]);

查询结果

Unknown column `WorkshopServices.service_id` in 'where clause'

实际上Workshops表格没有生成JOIN个WorkshopServices表格。

如何编写查询以从Query Builder获得正确的结果？

Answer 1

使用匹配：

$array = [1,2,3];

$this->Workshops->find()
    ->matching('WorkshopServices', function ($q) use($array) {
       return $q->where(['WorkshopServices.service_id IN' => $array])
    });

Answer 2

我更新了@ GabrielFerreira的查询并按WorkshopServices.workshop_id对行进行分组，此解决方案符合我的问题

$array = [1,2,3];

$this->Workshops->find()
    ->select([
          'title'=>'Workshops.title',
          'id'=>'Workshops.id',
    ])
    ->matching('WorkshopServices', function ($q) use($array) {
       return $q->where(['WorkshopServices.service_id IN' => $array]);
    })
    ->group(['WorkshopServices.workshop_id']);

CakePHP 3 - 查询构建器正常不适用于HasMany关联

2 个答案: