Question

我从String path = uri.getPath()获取了/document/primary:Download/West Delhi Mis June.xlsx

但是当我写File file = new File(path)时，它会抛出FileNotFoundException。请帮忙。

这是我的代码：

public void getdata(File fil){

    try{
        Workbook w;
        w = Workbook.getWorkbook(fil);
        Sheet sheet = w.getSheet(0);
        for (int j = 1; j<sheet.getRows(); j++){

            Cell c1 = sheet.getCell(0,j);
            Cell c2 = sheet.getCell(1,j);
            Cell c3 = sheet.getCell(2,j);
            Cell c4 = sheet.getCell(3,j);
            Cell c5 = sheet.getCell(4,j);
            Cell c6 = sheet.getCell(5,j);
            Cell c7 = sheet.getCell(6,j);
            Cell c8 = sheet.getCell(7,j);
            Cell c9 = sheet.getCell(8,j);
            Cell c10 = sheet.getCell(9,j);
            Cell c11 = sheet.getCell(10,j);
            Cell c12 = sheet.getCell(11,j);
            Cell c13 = sheet.getCell(12,j);

            String date =  c1.getContents();
            String empid = c2.getContents();
            String project = c3.getContents();
            String name =  c4.getContents();
            String route =  c5.getContents();
            String cabno = c6.getContents();
            String location =  c7.getContents();
            String contact = c8.getContents();
            String gender =  c9.getContents();
            String duty =  c10.getContents();
            String shift =  c11.getContents();
            String cabtype =  c12.getContents();
            String zone =  c13.getContents();

            adb.insertRoastData(date,empid,project,name,route,cabno,location,contact,gender,duty,shift,cabtype,zone);
        }
    }catch (Exception e){
        e.printStackTrace();
    }

}

public void performFileSearch() {

    Intent intent = new Intent(Intent.ACTION_OPEN_DOCUMENT);

    intent.addCategory(Intent.CATEGORY_OPENABLE);

    intent.setType("application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");

    startActivityForResult(intent, READ_REQUEST_CODE);
}

@Override
public void onActivityResult(int requestCode, int resultCode,
                             Intent resultData) {
    if (requestCode == READ_REQUEST_CODE && resultCode == Activity.RESULT_OK) {
        Uri uri = null;
        if (resultData != null) {
            uri = resultData.getData();
            String path = uri.getPath();
            InputStream dataStream = this.getContentResolver().openInputStream(path);

        }
    }
}

Answer 1

您无法直接将Uri转换为文件 Uri甚至可能不包含真正的绝对路径。

这是因为它可能必须通过来自不同应用程序的ContentProvider来为您提供实际文件，这是Nougat的新文件安全模型的所有部分。

那你能做什么？让操作系统将其作为InputStream打开：

Uri uri = ...
InputStream dataStream = context.getContentResolver().openInputStream(uri);
// now buffer and read stream

如何将uri从onActivityresult转换为真实文件路径以导入该文件

1 个答案: