Question

我想获取图片的网址。 XML文档树如下：

<rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
<channel>
    <title>
        <![CDATA[ The Star Online Business Highlights ]]>
    </title>
    <link>/TheStar/Website</link>
    <description>...</description>
    <image>...</image>
    <language>en</language>
    <item>
        <guid isPermaLink="false">{F88B27DD-24FB-4807-941F-070D772B7586}</guid>
        <link>
            http://www.thestar.com.my/business/business-news/2017/10/24/top-glove-says-not-buying-adventa-nor-supermax/
        </link>
        <title>
            <![CDATA[ Top Glove says not buying Adventa nor Supermax ]]>
        </title>
        <description>
            <![CDATA[KUALA LUMPUR: Top Glove, which has allocated about RM1bil to expand via mergers, has denied news reports the target companies are Adventa Bhd and Supermax Corporation Bhd.]]>
        </description>
        <pubDate>Tue, 24 Oct 2017 13:17:18 +08:00</pubDate>
        <enclosure url="http://www.thestar.com.my/~/media/online/2017/08/22/03/58/hartalega-glove3.ashx?crop=1&w=0&h=0&" length="" type="image/jpeg"/>
        <media:content url="http://www.thestar.com.my/~/media/online/2017/08/22/03/58/hartalega-glove3.ashx?crop=1&w=0&h=0&" type="image/jpeg">
            <media:description>
                <![CDATA[ ]]>
            </media:description>
        </media:content>
        <section>
            <![CDATA[ Business ]]>
        </section>
    </item>
    <item>...</item>
    <item>...</item>
    <item>...</item>
</channel>

由于有多个项目，我想让它成为一个循环，我尝试了：

foreach($xml->channel->item as $news) { 
    $media = $news->media->children('http://search.yahoo.com/mrss/');
    echo ($media->content);
}

以及

foreach($xml->channel->item as $news) { 
    $media = $news->children('http://search.yahoo.com/mrss/');
    echo ($media->content);
}

但两者似乎都失败了。什么是正确的方法？

Answer 1

inputs_layer

Answer 2

$media变量的类型为SimpleXMLElement。您可以做的是将$media变量循环到foreach中，然后从attributes获取url。

例如（使用simplexml_load_string和additional Libxml parameters加载示例xml：

$source = <<<SOURCE
//Your example xml here
SOURCE;

$xml = simplexml_load_string($source, "SimpleXMLElement", LIBXML_NOERROR|LIBXML_ERR_NONE|LIBXML_ERR_FATAL);

foreach($xml->channel->item as $news) {
    $media = $news->children('http://search.yahoo.com/mrss/');
    foreach($media as $child) {
        echo $child->attributes()->url;
    }
}

将导致：

http://www.thestar.com.my/~/media/online/2017/08/22/03/58/hartalega-glove3.ashx?crop=1=0=0

使用PHP获取XML属性

2 个答案: