Question

我有一个依赖于shell脚本生成的图形文件的库。

我希望这个库在编译时能够使用shell脚本生成图形文件，这些文件应该被复制，好像它是一个'data'语句，但每当我试图让库依赖于它时genrule，我得到

在cc_library规则// graphics_assets的deps属性中 genrule rule'// graphics_assets：assets_gen_rule'在这里放错了地方（预期cc_inc_library，cc_library，objc_library或 cc_proto_library）

Answer 1


        # This is the correct format.
        # Here we want to run all the shader .glsl files through the program     
        # file_utils:archive_tool (which we also build elsewhere) and copy the 
        # output .arc file to the data.

        # 1. List the source files

        filegroup(
            name = "shader_source",
            srcs = glob([
                "shaders/*.glsl",
            ]),
        )

        # 2. invoke file_utils::archive_tool on the shaders

        genrule(
            name = "shaders_gen_rule",
            srcs = [":shader_source"],
            outs = ["shaders.arc"],
            cmd = "echo $(locations shader_source) > temp.txt ;  \
              $(location //common/file_utils:archive_tool)  \
               --create_from_list=temp.txt \
               --archive $(OUTS)  ;   \
              $(location //common/file_utils:archive_tool)   \
              --ls --archive $(OUTS) ",
            tools = ["//common/file_utils:archive_tool"],
        )

        # 3. when a a binary depends on this tool the arc file will be copied.
        # This is the thing I had trouble with

        cc_library(
            name = "shaders",
            srcs = [], # Something
            data = [":shaders_gen_rule"],
            linkstatic = 1,
        )

在Bazel中，如何使C ++库依赖于一般规则？

1 个答案: