Question

我有一个名为ConsignmentCode的MySql记录表。我想发送一个HTTP请求来通过ConsignmentCode搜索表。

当我使用Postman向http://localhost:8081/records/consignmentCode的{consignmentCode: "123456789"}发送POST请求时，我收到404 Not Found错误。有谁知道为什么？

控制器类：

  /**
     * POST request to search by ConsignmentCode
     *
     * /records/consignmentCode
     *
     * Input ex: {consignmentCode: "123456789"}
     * @param params
     * @return
     */

    @CrossOrigin
    @ResponseBody
    @RequestMapping(
            value = "/consignmentCode",
            method = RequestMethod.POST,
            consumes= MediaType.APPLICATION_JSON_VALUE)
    public java.lang.String SearchRecordsByConsignmentCode(@RequestBody String params) {
        System.out.print("this SearchRecordsByConsignmentCode respond happened");
        JSONObject obj = new JSONObject();
        JSONObject jsonObj = new JSONObject(params);
        String likeConsignment= jsonObj.getString("consignmentCode");

        List<record> results=RecordDao.SearchRecordsByConsignmentCode(likeConsignment);
        obj.put("results", results);
        return obj.toString();
    }

道上课：

 /**
     * Search by ConsignmentCode.
     *
     * @param consignmentCode
     * @return
     */

    public List<record> SearchRecordsByConsignmentCode(String consignmentCode) {
        final String sql = "SELECT * FROM records WHERE ConsignmentCode = ?";
        List<record> Record = jdbcTemplate.query(sql, new RowMapper<record>() {
            public record mapRow(ResultSet resultSet, int Id) throws SQLException {
                record records = new record();
                records.setId(resultSet.getInt("Id"));
                records.setNumber(resultSet.getString("Number"));
                records.setTitle(resultSet.getString("Title"));
                records.setScheduleId(resultSet.getInt("ScheduleId"));
                records.setTypeId(resultSet.getInt("TypeId"));
                records.setConsignmentCode(resultSet.getString("ConsignmentCode"));
                records.setStateId(resultSet.getInt("StateId"));
                records.setContainerId(resultSet.getInt("ContainerId"));
                records.setLocationId(resultSet.getInt("LocationId"));
                records.setCreatedAt(resultSet.getDate("CreatedAt"));
                records.setUpdatedAt(resultSet.getDate("UpdatedAt"));
                records.setClosedAt(resultSet.getDate("ClosedAt"));
                System.out.print(records);
                return records;
            }
        }, consignmentCode);
        return Record;
    }

Answer 1

使用：

@RequestBody String consignmentCode

而不是：

@RequestBody String params

Answer 2

您不必期望接收String然后解析为JSon。它是Spring MVC中的内置行为。

只需导入jackson-dependencies。如果您使用Maven，请添加您的pom.xml依赖项：

<dependency>
    <groupId>org.codehaus.jackson</groupId>
    <artifactId>jackson-mapper-asl</artifactId>
    <version>1.9.9</version>
</dependency>
<dependency>
    <groupId>org.codehaus.jackson</groupId>
    <artifactId>jackson-core-asl</artifactId>
    <version>1.9.9</version>
</dependency>

然后以这种方式更改控制器：

@Controller
public class RestController {

    @ResponseBody
    @RequestMapping(
            value = "/consignmentCode",
            method = RequestMethod.POST,
            consumes= MediaType.APPLICATION_JSON_VALUE)
    public List<Record> SearchRecordsByConsignmentCode(@RequestBody ConsignmentCode code) {
        System.out.print("this SearchRecordsByConsignmentCode respond happened");

        List<Record> results=RecordDao.SearchRecordsByConsignmentCode(code.getConsignmentCode());
        return results;
    }

您需要创建一个封装消息正文的类：

import java.io.Serializable;

public class ConsignmentCode implements Serializable {

    private String consignmentCode;

    public String getConsignmentCode() {
        return consignmentCode;
    }

    public void setConsignmentCode(String consignmentCode) {
        this.consignmentCode = consignmentCode;
    }   


}

然后，启动它并尝试向您的控制器发送此消息（请记住将Accept / Content-Type标头设置为application/json）。属性名称也必须在分号之间，这样：

{"consignmentCode":"123456789"}

您将以json格式获得正确的结果

使用Spring框架发送POST请求

2 个答案: