Question

我创建了一个采用任意文件的端点：

[HttpPost()]
public async Task<IActionResult> CreateFile(IFormFile file)

当我使用Postman测试时，file始终为空。

以下是我在Postman中所做的事情：

我做错了什么？

Answer 1

感谢@ rmjoia的评论，我得到了它的工作！这是我在邮差中必须做的事情：

Answer 2

一个或多个文件上传的完整解决方案如下所示：

此操作用于上传多个文件：

// Of course this action exist in microsoft docs and you can read it.
HttpPost("UploadMultipleFiles")]
public async Task<IActionResult> Post(List<IFormFile> files)
{

    long size = files.Sum(f => f.Length);

    // Full path to file in temp location
    var filePath = Path.GetTempFileName();

    foreach (var formFile in files)
    {
        if (formFile.Length > 0)
            using (var stream = new FileStream(filePath, FileMode.Create))
                await formFile.CopyToAsync(stream);
    }

    // Process uploaded files

    return Ok(new { count = files.Count, path = filePath});
}

邮递员图片显示了如何将文件发送到此端点以上传多个文件：

此操作用于上传单个文件：

[HttpPost("UploadSingleFile")]
public async Task<IActionResult> Post(IFormFile file)
{

    // Full path to file in temp location
    var filePath = Path.GetTempFileName();

    if (file.Length > 0)
        using (var stream = new FileStream(filePath, FileMode.Create))
            await file.CopyToAsync(stream);

    // Process uploaded files

    return Ok(new { count = 1, path = filePath});
}

邮递员图片显示了如何将文件发送到此端点以上传单个文件：

Answer 3

您应该是这样

 [HttpPost]       
   public async Task<IActionResult> UploadFile([FromForm]UploadFile updateTenantRequest)
        {
}

您的课程应该像：-

public class UpdateTenantRequestdto
    {


        public IFormFile TenantLogo { get; set; }
    }

然后

Answer 4

   [HttpPost("UploadSingleFile"), Route("[action]")]
    public async Task<IActionResult> UploadSingleFile([FromForm(Name = "file")] IFormFile file)
    {


        // Process uploaded files

        string folderName = "Uploads";
        string webRootPath = hostingEnvironment.WebRootPath;
        string newPath = Path.Combine(webRootPath, folderName);
        if (!Directory.Exists(newPath))
        {
            Directory.CreateDirectory(newPath);
        }

        Repository.Models.File fileModel = new Repository.Models.File();
        fileModel.Name = ContentDispositionHeaderValue.Parse(file.ContentDisposition).FileName.Trim('"');
        fileModel.Path = $"{folderName}/{file.FileName}";
        fileModel.Size = file.Length;
        fileModel.Type = file.ContentType;

        string fullPath = Path.Combine(newPath, fileModel.Name);

        fileModel.Extension = Path.GetExtension(fullPath);
        fileModel.CreatedDate = Utility.Common.GetDate;
        fileModel.CreatedBy = 1;

        //fileModel save to db

        using (var stream = new FileStream(fullPath, FileMode.Create))
        {
            //file.CopyTo(stream);
            await file.CopyToAsync(stream);
        }

        return Ok(new { count = 1, path = filePath });
    }

使用Postman上传ASP核心WebApi测试文件

4 个答案: