id POSTINGS
1 [9,9,9,9,9,9,9,9]
2 [9,9,9,9,9,9,9,9]
3 [9,0,0,0,0,0,0,0]
4 [9,1,2,0,0,0,0,0]
5 [9,9,9,9,9,9,9,9]
6 [9,9,9,9,9,8,9,9]
7 [9,9,9,9,9,9,8,9]
8 [9,9,9,9,8,8,9,9]
这里我试图在POSTING列中添加值列表并将结果存储在新的“SUM”列中
预期输出
id POSTINGS SUM
1 [9,9,9,9,9,9,9,9] 56
2 [9,9,9,9,9,9,8,8] 54
3 [9,0,0,0,0,0,0,0] 9
4 [9,1,2,0,0,0,0,0] 12
5 [9,9,9,9,9,9,9,9] 56
6 [9,9,9,9,9,8,9,9] 55
7 [9,9,9,9,9,9,8,9] 55
8 [9,9,9,9,8,8,9,9] 54
答案 0 :(得分:2)
您可以使用sum
中的内置apply
功能,然后您将获得一个包含POSTINGS
中列表总和的列:
df['SUM'] = df['POSTINGS'].apply(sum)