我对Rest Sharp和Postman仍然很新，但我正试图做一个＆＃34;更新＆＃34;到现有用户。这是我的代码，但我知道它错了。有没有人有关于如何执行＆＃34;替换＆＃34;在夏普休息时操作？
string url = _EndPoint + "?_action = patch & _queryId =for-userName & uid =" + obj.userName.ToString();
var client = new RestClient(url);
var request = new RestRequest(Method.POST);
string username = "openidm-admin";
string password = "openidm-admin";
string svcCredentials = Convert.ToBase64String(ASCIIEncoding.ASCII.GetBytes(username + ":" + password));
string Update = BuildUpdate();
//if (Update != null)
//{
request.AddHeader("Authorization", "Basic " + svcCredentials);
request.AddHeader("content-type", "application/json");
//request.AddParameter("application/json", "[\n {\n \"operation\": \"replace\",\n \"field\": \"/userName\",\n \"value\": \"testuser4@aha.org\"\n },\n {\n \"operation\": \"replace\",\n \"field\": \"/mail\",\n \"value\": \"testuser4@aha.org\"\n }\n]", ParameterType.RequestBody);
request.AddBody({ "operation": "replace", "field": "/userName", "value": "testuser4@aha.org"}, { "operation": "replace", "field": "/mail", "value": "testuser4@aha.org"});
IRestResponse response = client.Execute(request);
邮递员说它应该是这样的：
[
{
"operation": "replace",
"field": "/userName",
"value": "testuser4@aha.org"
},
{
"operation": "replace",
"field": "/mail",
"value": "testuser4@aha.org"
}
]
我更愿意这样写，但我不知道怎么做。其他代码建议我创建一个字符串。我可以通过字符串写出来，但如果我能或可能，我更喜欢在体内写出来。提前致谢
修改
这是我的班级：
public class IdentityDetails
{
//public const string type = "user";
//public const string realm = "dc=aha,dc=org";
public string userName { get; set; }
public string mail { get; set; }
public string givenName { get; set; }
public string sn { get; set; }
public string accountStatus { get; set; }
public string avectraId { get; set; }
public string AHApw { get; set; }
public string password { get; set; }
public string ahaBirthYear { get; set; }
public string city { get; set; }
public string ahaGender { get; set; }
public string ahaJobTitle { get; set; }
public string ahaLeadScore { get; set; }
public string stateProvince { get; set; }
public string orgId { get; set; }
public string[] ahaMemberGroup { get; set; }
public string[] ahaMemberType { get; set; }
public string regMethod { get; set; }
//public string[] ahaDrupalPermission { get; set; }
}
我认为我需要做的就是传递当前字段和值，并传入字段的新值。我只是在寻找使用Restsharp执行更新请求的其他人的示例代码。我可以用字符串写出来，但是我希望有一种更简单的方法，然后使用字符串并作为参数传递。
修改
我目前正试图通过构建一个字符串作为参数传入来实现。我知道必须有更好的方法。以下是我目前在构建字符串方面的进展;
Postman String：
request.AddParameter("application/javascript", "[\n {\n \"operation\": \"replace\",\n \"field\": \"/userName\",\n \"value\": \"testuser4@aha.org\"\n },\n {\n \"operation\": \"replace\",\n \"field\": \"/mail\",\n \"value\": \"testuser4@aha.org\"\n }\n]", ParameterType.RequestBody);
我的字符串构建器功能正在进行中：
private string BuildUpdate(string field, string newvalue, string oldvalue)
{
try
{
string Update = string.Empty;
string UpdateOperation = '"' + "operation" + '"' + ": " + '"' + "replace\"" + ",\n" + '"';
string Updatefield = "field" + '"' + ": \"";
string UpdateNewValue = "/" + newvalue + '"' + ",\n";
string
// "[\n {\n \"operation\": \"replace\",\n\"
// field\": \"
// /userName\",\n
// \"value\": \"testuser4@aha.org\"\n },\n {\n \"operation\": \"replace\",\n \"field\": \"/mail\",\n \"value\": \"testuser4@aha.org\"\n }\n]"
return Update;
}
catch(Exception ex)
{
return null;
}
}
任何人都有更好的方法吗？
答案 0 :(得分：0)
我想我找到了问题的答案。我不确定我是否按照正确的顺序排列了这个，但我的字符串格式正确。我希望这对其他人也有帮助。
这是我使用Restsharp执行REST更新请求的基本功能：
public string UpdateRequest(string uid, string field, string newvalue, string oldvalue)
{
try
{
string url = _EndPoint + "?_action = patch & _queryId =for-userName & uid =" + uid;
var client = new RestClient(url);
var request = new RestRequest(Method.POST);
string username = "openidm-admin";
string password = "openidm-admin";
string svcCredentials = Convert.ToBase64String(ASCIIEncoding.ASCII.GetBytes(username + ":" + password));
string Update = BuildUpdate(field, newvalue, oldvalue);
if (Update != null)
{
request.AddHeader("Authorization", "Basic " + svcCredentials);
request.AddHeader("content-type", "application/json");
request.AddParameter("application/json", Update, ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
return response.Content.ToString();
}
else
{
//Error
return "Error";
}
}
catch (Exception ex)
{
return ex.ToString();
}
}
我正在调用我的BuildUpdate函数来返回我将用作传入参数的Json字符串。这是我构建更新字符串的函数。我将其分成两部分，并将每个部分转换为json字符串格式。然后我将它们组合成一个字符串：
private string BuildUpdate(string field, string newvalue, string oldvalue)
{
try
{
//Parameter String
string Update = string.Empty;
//New Value
var dict1 = new Dictionary<string, string>();
dict1.Add("operation", "replace");
dict1.Add("field", field);
dict1.Add("value", newvalue);
string json1 = Regex.Unescape(JsonConvert.SerializeObject(dict1, Newtonsoft.Json.Formatting.Indented));
//Current Value
var dict2 = new Dictionary<string, string>();
dict2.Add("operation", "replace");
dict2.Add("field", field);
dict2.Add("value", oldvalue);
string json2 = Regex.Unescape(JsonConvert.SerializeObject(dict2, Newtonsoft.Json.Formatting.Indented));
Update = json1 + ",\n " + json2;
return Update;
}
catch(Exception ex)
{
return null;
}
}
这是我将输入的输出字符串作为我的参数：
"{\r\n \"operation\": \"replace\",\r\n \"field\": \"userName\",\r\n \"value\": \"testuser999@aha.org\"\r\n},\n {\r\n \"operation\": \"replace\",\r\n \"field\": \"userName\",\r\n \"value\": \"testuser4@aha.org\"\r\n}"
更新： 我只想与大家分享我的工作代码示例。
功能1：
public string UpdateRequest(string uid, string field, string value)
{
try
{
string url = _EndPoint + "?_action=patch&_queryId=for-userName&uid=" + uid;
var client = new RestClient(url);
var request = new RestRequest(Method.POST);
string username = "openidm-admin";
string password = "openidm-admin";
string svcCredentials = Convert.ToBase64String(ASCIIEncoding.ASCII.GetBytes(username + ":" + password));
string Update = BuildUpdate(field, value);
if (Update != null)
{
request.AddHeader("Authorization", "Basic " + svcCredentials);
request.AddHeader("content-type", "application/json");
request.AddParameter("application/json", Update, ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
return response.Content.ToString();
}
else
{
//Error
return "Error";
}
}
catch (Exception ex)
{
return ex.ToString();
}
}
以下是为请求构建Json字符串的字符串构建函数：
private string BuildUpdate(string field, string value)
{
try
{
//Parameter String
string json = string.Empty;
//Value
var dict = new Dictionary<string, string>();
dict.Add("operation", "replace");
dict.Add("field", field);
dict.Add("value", value);
json = "[\n" + Regex.Unescape(JsonConvert.SerializeObject(dict, Newtonsoft.Json.Formatting.Indented)) + "\n]";
return json;
}
catch(Exception ex)
{
return null;
}
}
我不知道为什么我要添加“[\ n”或“\ n]”但我认为它包装它是出于某种原因。无论如何，我希望这有助于某人。