Question

我有以下代码

import subprocess
interestedYears=5;
year=1
today="2017-10-23"
tokenDataToday= today.split("-")
dateEnd=tokenDataToday[0]+tokenDataToday[1]+tokenDataToday[2]
url= "https://addons.mozilla.org/en-US/firefox/addon/adblock-plus/statistics/downloads-day-"

while year <= interestedYears:
     yearStart= str(int(float(tokenDataToday[0]))-year)
     dateStart=yearStart+tokenDataToday[1]+tokenDataToday[2]
     #print("dateStart: " + dateStart)
     #print("dateEnd: " + dateEnd)
     tmpUrl=url+dateStart+"-"+dateEnd+".csv"
     cmd = 'curl -O ' + tmpUrl
     print(cmd)
     args = cmd.split()
     process = subprocess.Popen(args, shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
     stdout, stderr = process.communicate()
     dateEnd=dateStart
     year = year+1
     print("-----------------------------")

使用curl后我得到了这个字符串。然后我想得到所有标签的所有链接（href链接）与class＆class 39 class2＆＃39;，怎么做？我尝试了一些方法，但它不起作用：（

Answer 1

使用DOMDocument

$dom = new DOMDocument;
// load your html
$dom->loadHTML($input);
// loop all the anchor tags 
foreach ($dom->getElementsByTagName('a') as $a) {
     // check the calss
     if($a->getattribute('class') == 'class1 class2') {
          // echo href 
          echo $a->getattribute('href')."<br/>";
     }
}

Out put：

link-to-web1.html
abc/link-to-web1.html
abc/xyz/link-to-web1.html

如何在PHP中获取标签内的链接html（html为纯文本）？

1 个答案: