考虑以下数据框:
import pandas as pd
df = pd.DataFrame(["What is the answer",
"the answer isn't here, but the answer is 42" ,
"dogs are nice",
"How are you"], columns=['words'])
df
words
0 What is the answer
1 the answer isn't here, but the answer is 42
2 dogs are nice
3 How are you
我想计算某个字符串的出现次数,可能会在每个索引中重复几次。
例如,我想计算the answer
出现的次数。
我试过了:
df.words.str.contains(r'the answer').count()
我希望找到解决方案,但输出为4
。
我不明白为什么。 the answer
出现了3次。
What is **the answer**
**the answer** isn't here, but **the answer** is 42
注意:搜索字符串可能会在行中出现多次
答案 0 :(得分:4)
您需要str.count
In [5285]: df.words.str.count("the answer").sum()
Out[5285]: 3
In [5286]: df.words.str.count("the answer")
Out[5286]:
0 1
1 2
2 0
3 0
Name: words, dtype: int64