Question

我希望有一台正在运行的服务器，并从其他Java应用程序等客户端接收消息。我通过带有InputStream的BufferedReader执行此操作，只要我一次按预期工作。消息由方法处理并在屏幕上写入接收消息的测试消息，但是如果我让它在while循环中运行则表示 -

COMMAND=`eval aws ecr get-login --region us-west-2`
echo `eval $COMMAND`

因此，一旦服务器收到消息，我就不知道如何获得第二个或任何后续的消息。

我的主要源代码是：

java.net.SocketException: Connection reset

创建流的两个类看起来像这样：

public static void main (String[] args)  {

    int port = 13337;
    BufferedReader msgFromClient = null;
    PrintWriter msgToClient = null;

    timeDate td = new timeDate(); //Class i did for myself to get time/date

    ServerSocket s_socket = null;
    try {
        s_socket = new ServerSocket(port);
        System.out.println("Server startet at "+td.getCurrDate()+" "+td.getCurrTime());
    }
    catch (IOException ioe) {
        System.out.println("Server on Port "+port+" couldnt be created. \nException: "+ioe.getMessage());
    }

    Socket socket = null;
    try {
        socket = s_socket.accept();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    try {
        msgFromClient = utils.createInputStream(socket);
    } catch (IOException ioe) {
        System.out.println("Creation of an Input Stream failed.\n Exception - "+ioe);
    }
    try {
        msgToClient   = utils.createOutputStream(socket);
    } catch (IOException ioe) {
        System.out.println("Creation of an Output Stream failed.\n Exception - "+ioe);
    } 

    String input = null;
    while (true) {
            try {
                input = msgFromClient.readLine();
            } catch (IOException ioe) {
                System.out.println(ioe);
            }
            if(input!=null) {
                System.out.println("Jumping out of loop: "+input);
                utils.processCode(input);
            }
    }

＆＃34; processCode＆＃34;然后，班级只是一个开关。

Answer 1

Socket socket = null;
try {
    socket = s_socket.accept();
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

您只接受一个连接，此后您正在进行处理。您需要为每个连接打开一个新的线程

ExecutorService threadLimit = Executors.newFixedThreadPool(10);
    while(true)  {
        Socket s = serverSocket.accept();
        treadLimit.submit(new HandleThread(s));
    }

如何让服务器从客户端收到多条消息？

1 个答案: