问题看似简单,虽然我找不到合适的解决方案 因为我缺乏HTML和Javascript的知识。
任务只是设计一个网页,其中一个按钮将激活网络摄像头,并在本地硬盘中存储静止图像或视频(最好)。暂时不需要上传/下载。
经过一些尝试后,我可以使用getusermedia()API激活网络摄像头并在浏览器窗口中渲染视频,但无法保存。这就是我的代码。
if (navigator.getUserMedia) {
navigator.getUserMedia({video: true}, handleVideo, videoError);
}
function handleVideo(stream) {
video.src = window.URL.createObjectURL(stream);
}
所以关于如何在硬盘中保存静止图像或视频的任何想法都以同样的方式捕获?
答案 0 :(得分:6)
首先,不推荐使用navigator.getUserMedia
API,现在应该使用navigator.mediaDevices.getUserMedia
方法。
然后拍摄静止图像,您确实可以使用可以draw视频元素的画布。
const vid = document.querySelector('video');
navigator.mediaDevices.getUserMedia({video: true}) // request cam
.then(stream => {
vid.srcObject = stream; // don't use createObjectURL(MediaStream)
return vid.play(); // returns a Promise
})
.then(()=>{ // enable the button
const btn = document.querySelector('button');
btn.disabled = false;
btn.onclick = e => {
takeASnap()
.then(download);
};
})
.catch(e=>console.log('please use the fiddle instead'));
function takeASnap(){
const canvas = document.createElement('canvas'); // create a canvas
const ctx = canvas.getContext('2d'); // get its context
canvas.width = vid.videoWidth; // set its size to the one of the video
canvas.height = vid.videoHeight;
ctx.drawImage(vid, 0,0); // the video
return new Promise((res, rej)=>{
canvas.toBlob(res, 'image/jpeg'); // request a Blob from the canvas
});
}
function download(blob){
// uses the <a download> to download a Blob
let a = document.createElement('a');
a.href = URL.createObjectURL(blob);
a.download = 'screenshot.jpg';
document.body.appendChild(a);
a.click();
}
&#13;
<button>take a snapshot</button>
<video id="vid"></video>
&#13;
As a fiddle因为Stacksnippets可能会阻止gUM请求...
要保存为视频,您可以使用[MediaRecorder API](https://developer.mozilla.org/en-US/docs/Web/API/MediaRecorderà,这样您就可以将MediaStream保存为webm:
const vid = document.querySelector('video');
navigator.mediaDevices.getUserMedia({video: true}) // request cam
.then(stream => {
vid.srcObject = stream; // don't use createObjectURL(MediaStream)
return vid.play(); // returns a Promise
})
.then(()=>{ // enable the button
const btn = document.querySelector('button');
btn.disabled = false;
btn.onclick = startRecording;
})
.catch(e=>console.log('please use the fiddle instead'));
function startRecording(){
// switch button's behavior
const btn = this;
btn.textContent = 'stop recording';
btn.onclick = stopRecording;
const chunks = []; // here we will save all video data
const rec = new MediaRecorder(vid.srcObject);
// this event contains our data
rec.ondataavailable = e => chunks.push(e.data);
// when done, concatenate our chunks in a single Blob
rec.onstop = e => download(new Blob(chunks));
rec.start();
function stopRecording(){
rec.stop();
// switch button's behavior
btn.textContent = 'start recording';
btn.onclick = startRecording;
}
}
function download(blob){
// uses the <a download> to download a Blob
let a = document.createElement('a');
a.href = URL.createObjectURL(blob);
a.download = 'recorded.webm';
document.body.appendChild(a);
a.click();
}
&#13;
<button disabled>start recording</button>
<video></video>
&#13;
一样
注意:
MediaRecorder API仍然是一个非常新的API,[一小部分浏览器实现中仍然存在一些错误。
答案 1 :(得分:0)
你所做的是一个好的开始。您现在可以'paint' the webcam picture into a canvas然后create an image from the canvas information。然后,您可以使用一些技巧来阻止浏览器显示图像并将其转到download it instead。