Question

如果我使用

$categories= Category::orderby('id', 'desc')->paginate(3);

它有效，但如果我使用

$categories= Category::with('subcategories')->orderby('id', 'desc')->paginate(3);

paginate不起作用！如何解决？

更新：

<tbody>
@foreach ($categories as $category)
 @foreach($category->subcategories as $sub)
  <tr>
    <td class="text-center">{{ $sub->id }}</td>
    <td class="text-center">{{ $sub->title }}</td>
    <td class="text-center">{{ $sub->category->title }}</td>
  </tr>
 @endforeach
@endforeach
</tbody>

Answer 1

你需要从关系的另一面来解决这个问题。

查找所有子类别及其父类别，按ID降序排序，然后每页分页三个。

$subcategories = Subcategory::with('category')
    ->orderBy('id', 'desc')
    ->paginate(3);

<tbody>
    @foreach($subcategories as $subcategory)
        <tr>
            <td class="text-center">{{ $subcategory->id }}</td>
            <td class="text-center">{{ $subcategory->title }}</td>
            <td class="text-center">{{ $subcategory->category->title }}</td>
        </tr>
    @endforeach
</tbody>

Laravel在查询生成器上分页

1 个答案: