目前,我创建了自定义函数来创建,以便从Moment中找到fromNow,我想根据函数返回的值对数据进行排序。
我想将表格元素放在顶部从现在开始的日期较小
在下表中从今天开始的31天在第二列是较小的,我想把这个元素放在顶部,我尝试过以下方式,但它没有工作
有人能帮助我吗? 表
AngularJS OrderBy
<tr ng-repeat="x in Holidays|orderBy:findFromNow">
<td>{{$index+1}}</td>
<td>{{x.Day}}</td>
<td>
<span class="label label-warning">{{findFromNow(x.Date)}} Days From Today</span></td>
</tr>
功能
$scope.findFromNow = function (inputDate) {
var m = moment(inputDate, "D-MMM-YY");
var today = moment().startOf('day');
var days = Math.round((today - m) / 86400000);
if (days > 0) {
return 999;
} else {
return (days * (-1));
}
}
假期JSON
[
{
"Day": "Monday",
"Date": "2-Jan-17"
},
{
"Day": "Monday",
"Date": "20-Feb-17"
},
{
"Day": "Monday",
"Date": "29-May-17"
},
{
"Day": "Monday",
"Date": "3-Jul-17"
},
{
"Day": "Tuesday",
"Date": "4-Jul-17"
},
{
"Day": "Monday",
"Date": "4-Sep-17"
},
{
"Day": "Thursday",
"Date": "23-Nov-17"
},
{
"Day": "Friday",
"Date": "24-Nov-17"
},
{
"Day": "Monday",
"Date": "25-Dec-17"
}
]
答案 0 :(得分:2)
你应该在使用前刻写单独的函数或检查inputDate的类型,因为在orderBy中,inputDate是Object not Date
$scope.sortDate = function(inputDate){
var m = moment(inputDate.Date, "D-MMM-YY");
var today = moment().startOf('day');
var days = Math.round((today - m) / 86400000);
if (days > 0) {
return 999;
} else {
return (days * (-1));
}
}
这是plnkr:
希望有所帮助