所以,我正在尝试为简单的游戏制作一个基本的功能菜单。我尝试通过创建2个JPanel来实现这一点,一个用于实际游戏,另一个用于我的菜单。
我要做的是在我的菜单面板上有一个按钮,当按下该按钮时,将在父JFrame中显示的JPanel从菜单的显示切换到实际游戏的JPanel。
这是我的代码:
class Menu extends JPanel
{
public Menu()
{
JButton startButton = new JButton("Start!");
startButton.addActionListener(new Listener());
add(startButton);
}
private class Listener implements ActionListener
{
public void actionPerformed(ActionEvent e)
{
Container container = getParent();
Container previous = container;
System.out.println(getParent());
while (container != null)
{
previous = container;
container = container.getParent();
}
previous.setContentPane(new GamePanel());
}
}
}
如您所见,我为我的开始按钮创建了一个监听器。在监听器内部,我使用while循环通过getParent()
方法访问JFrame。该程序正在获取JFrame对象,但它不允许我调用setContentPane
方法...
有谁知道如何让这个工作,或者更好的方式在菜单和游戏之间来回切换?
答案 0 :(得分:3)
像这样:
public class CardLayoutDemo extends JFrame {
public final String YELLOW_PAGE = "yellow page";
public final String RED_PAGE = "red page";
private CardLayout cLayout;
private JPanel mainPane;
boolean isRedPaneVisible;
public CardLayoutDemo(){
setTitle("Card Layout Demo");
setSize(400,250);
setDefaultCloseOperation(EXIT_ON_CLOSE);
mainPane = new JPanel();
cLayout = new CardLayout();
mainPane.setLayout(cLayout);
JPanel yellowPane = new JPanel();
yellowPane.setBackground(Color.YELLOW);
JPanel redPane = new JPanel();
redPane.setBackground(Color.RED);
mainPane.add(YELLOW_PAGE, yellowPane);
mainPane.add(RED_PAGE, redPane);
showRedPane();
JButton button = new JButton("Switch Panes");
button.addActionListener(e -> switchPanes() );
setLayout(new BorderLayout());
add(mainPane,BorderLayout.CENTER);
add(button,BorderLayout.SOUTH);
setVisible(true);
}
void switchPanes() {
if (isRedPaneVisible) {showYelloPane();}
else { showRedPane();}
}
void showRedPane() {
cLayout.show(mainPane, RED_PAGE);
isRedPaneVisible = true;
}
void showYelloPane() {
cLayout.show(mainPane, YELLOW_PAGE);
isRedPaneVisible = false;
}
public static void main(String[] args) {
new CardLayoutDemo();
}
}