我有一个自定义的Exception类,我想在发生异常时将其作为json返回。
SpringCacheException.java
@JsonSerialize
public class SpringCacheException extends Exception{
private static final long serialVersionUID = 1L;
private HttpStatus status;
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd-MM-yyyy hh:mm:ss")
private LocalDateTime timestamp;
private String message;
private String debugMessage;
public SpringCacheException(HttpStatus status, String message, String debugMessage) {
super();
this.setStatus(status);
this.message = message;
this.debugMessage = debugMessage;
}
public SpringCacheException() {
timestamp = LocalDateTime.now();
}
public SpringCacheException(HttpStatus status) {
this();
this.setStatus(status);
}
public SpringCacheException(HttpStatus status, Throwable ex) {
this();
this.setStatus(status);
this.setMessage("Unexpected error");
this.setDebugMessage(ex.getLocalizedMessage());
}
public SpringCacheException(HttpStatus status, String message, Throwable ex) {
this();
this.setStatus(status);
this.setMessage(message);
this.setDebugMessage(ex.getLocalizedMessage());
}
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public String getDebugMessage() {
return debugMessage;
}
public void setDebugMessage(String debugMessage) {
this.debugMessage = debugMessage;
}
public HttpStatus getStatus() {
return status;
}
public void setStatus(HttpStatus status) {
this.status = status;
}
}
RestExceptionHandler.java
@Order(Ordered.HIGHEST_PRECEDENCE)
@ControllerAdvice
public class RestExceptionHandler extends ResponseEntityExceptionHandler {
private static final Logger logger= LoggerFactory.getLogger(ContactServiceImpl.class);
@Override
protected ResponseEntity<Object> handleMethodArgumentNotValid(MethodArgumentNotValidException ex, HttpHeaders headers, HttpStatus status, WebRequest request) {
SpringCacheException errorMessage = new SpringCacheException(status.BAD_REQUEST,"My Error",ex);
return new ResponseEntity<Object>(errorMessage, headers, status);
}
@ExceptionHandler(SpringCacheException.class)
ResponseEntity<Object> handleBadRequests(HttpStatus status,String message,SpringCacheException ex) throws IOException {
SpringCacheException errorMessage = new SpringCacheException(HttpStatus.BAD_REQUEST,"My Error",ex);
return new ResponseEntity<Object>(errorMessage,HttpStatus.BAD_REQUEST);
}
}
抛出异常: -
@Override
public Contact show(int id) throws SpringCacheException {
try {
Contact contact = contactRepository.findOneById(id);
return contact;
}
catch (Exception e) {
throw new SpringCacheException();
}
}
这里我将从数据库中删除联系人表,并抛出异常,我收到以下长时间的响应。
Position: 111
2017-10-22 00:37:08.577 WARN 10336 --- [nio-8080-exec-1] .m.m.a.ExceptionHandlerExceptionResolver : Failed to invoke @ExceptionHandler method: org.springframework.http.ResponseEntity<java.lang.Object> com.myapp.exception.RestExceptionHandler.handleBadRequests(org.springframework.http.HttpStatus,java.lang.String,com.myapp.exception.SpringCacheException) throws java.io.IOException
我只想要一个类型为SpringCacheException的json,但是我得到的这个长json的数据不正确。任何人都可以告诉我我做错了什么。谢谢!
找到整个代码答案 0 :(得分:1)
您的异常处理程序方法需要SpringCacheException对象的单个参数(其注释中的类)。
@ExceptionHandler(SpringCacheException.class)
ResponseEntity<Object> handleBadRequests(SpringCacheException ex) throws IOException {
//SpringCacheException errorMessage = new SpringCacheException(HttpStatus.BAD_REQUEST,"My Error",ex);
return new ResponseEntity<Object>(ex, HttpStatus.BAD_REQUEST);
}
}
顺便说一句,创建一个新的SpringCacheException会破坏该处理程序的目的。您应该返回传递给方法
的异常我将您的项目分叉并在此处修复:https://github.com/olantobi/SpringCaching