Question

我正在开发一个可以在其中输入文字的搜索栏的应用。

我希望应用程序然后打开“www.example.com/”来自搜索栏的“来自文本”，但唯一接触的是它实际上尝试打开www.example.com/dncode（这是不是真正的网址。）

非常感谢任何帮助。

感谢。

import UIKit

class ViewController: UIViewController, UISearchBarDelegate {

//connection that ties search bar in view to input for viewcontroller

@IBOutlet weak var searchbar: UISearchBar!


override func viewDidLoad() {
    super.viewDidLoad()
    searchbar.delegate = self
}
//activates keyboard etc when searchbar clicked
func searchBarSearchButtonClicked(_ searchbar: UISearchBar) {
    searchbar.resignFirstResponder()
    //(dncode) is string that will equal text as entered into search     bar

    let dncode = String()

    searchbar.text! = dncode

    if let url = URL (string: "https://www.example.com/(dncode)")
    {


        //this section to check and auto open URL in default browser     "Safari"
    if #available(iOS 10.0, *)
    {

        UIApplication.shared.open(url, options: [:], completionHandler: nil)
    } else {
        UIApplication.shared.openURL(url)
    }
}
}
}

Answer 1

您将搜索栏的文本设置为等于您的dncode变量，而不是反之亦然。你必须改变你的实施：

func searchBarSearchButtonClicked(_ searchbar: UISearchBar) {
    searchbar.resignFirstResponder()
    //(dncode) is string that will equal text as entered into search bar

    guard let dncode = searchbar.text else { return }

    if let url = URL (string: "https://www.example.com/(dncode)") {
        //this section to check and auto open URL in default browser     "Safari"
        if #available(iOS 10.0, *) {
            UIApplication.shared.open(url, options: [:], completionHandler: nil)
        } else {
            UIApplication.shared.openURL(url)
        }
    }
}

Answer 2

您必须替换：

let dncode = String()
searchbar.text! = dncode
if let url = URL (string: "https://www.example.com/(dncode)")

通过

 guard let dncode = searchbar.text else { return }   
 if let url = URL (string: "https://www.example.com/\(dncode)")

在Swift中，如何在UISearchbar中附加带有字符串的URL并在Safari中自动打开它？

2 个答案: