Here the vector of what i'm trying to do
这两个标签之间会有2个标签和一个图像视图,并且标识应该是不可点击的。
我几乎尝试了所有方法,但都失败了。
任何知道怎么做的人?
代码:
TabLayout tabLayout = (TabLayout) view.findViewById(R.id.tabs2);
tabLayout.setupWithViewPager(mViewPager);
tabLayout.getTabAt(1).setIcon(R.drawable.logo);
}
public class SectionsPagerAdapter extends FragmentPagerAdapter {
public SectionsPagerAdapter(FragmentManager fm) {
super(fm);
}
@Override
public Fragment getItem(int position) {
switch (position) {
case 0:
return new LeaderBoard();
case 1:
return new Logo();
case 2:
return new Recent_Post();
default:
return null;
}
}
@Override
public int getCount() {
// Show 3 total pages.
return 3;
}
@Override
public CharSequence getPageTitle(int position) {
switch (position) {
case 0:
return "LeaderBoard";
case 1:
return "";
case 2:
return "Recent Posts";
}
return null;
}
}
答案 0 :(得分:1)
我通过在彼此之间切换标签解决了我的问题,一些计算。
int currentScreen = 0;
mViewPager.addOnPageChangeListener(new ViewPager.OnPageChangeListener() {
@Override
public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
}
@Override
public void onPageSelected(int position) {
if (position == 1) {
if(currentScreen == 0) {
mViewPager.setCurrentItem(2);
currentScreen = 2;
}else{
mViewPager.setCurrentItem(0);
currentScreen = 0;
}
}
}
@Override
public void onPageScrollStateChanged(int state) {
}
});