Question

我即将对某个查询发疯，有人可以帮我翻译一个查询，以便在laravel中工作，或者以＆＃34; laravel方式编写＆＃34;。

查询代码如下，并且使用MySQL。

我遇到的部分是在第一个JOIN中，子查询到另一个JOIN它。

SELECT 
    usr.token,
    usr.id,
    usr.username,
    usr.sn,
    usr.givenname,
    usr.telefone_numero,
    usr.active,
    usr.unidade_id,
    usr.divisao_id,
    usr.secao_id,
    clients.nick,
    posto_grad.sigla AS quadro_sigla,
    log_logradouro_complemento,
    log_logr.nome AS log_logradouro_nome,
    log_logr.cep AS log_logradouro_cep,
    log_bairro.nome AS log_bairro_nome,
    log_localidade.nome AS log_localidade_nome,
    log_uf.sigla AS log_uf_sigla
FROM
    users usr
        LEFT JOIN
    (SELECT 
        usr_log1.*
    FROM
        users_log_logradouro AS usr_log1
    LEFT JOIN users_log_logradouro AS usr_log2 ON usr_log1.user_id = usr_log2.user_id
        AND usr_log1.created_at < usr_log2.created_at
    WHERE
        usr_log2.user_id IS NULL) AS temp ON (usr.id = temp.user_id)
        LEFT JOIN
    log_logradouro log_logr ON temp.log_logradouro_id = log_logr.id
        INNER JOIN
    clients ON clients.matricula = usr.givenname
        INNER JOIN
    quadro ON quadro.id = clients.quadro_id
        INNER JOIN
    posto_graduacao posto_grad ON posto_grad.id = clients.posto_graduacao_id
        LEFT JOIN
    log_bairro ON log_logr.log_bairro_id = log_bairro.id
        LEFT JOIN
    log_localidade ON log_bairro.log_localidade_id = log_localidade.id
        LEFT JOIN
    log_uf ON log_localidade.log_uf_sigla = log_uf.sigla
WHERE
    usr.departmentnumber IN (1,2,3,4)

Answer 1

尝试将子查询作为原始表达式发送为 leftJoin（）方法中的第一个参数，例如：

$subquery = '(SELECT 
                    usr_log1.*
                FROM
                    users_log_logradouro AS usr_log1
                LEFT JOIN 
                    users_log_logradouro AS usr_log2 
                    ON usr_log1.user_id = usr_log2.user_id
                    AND usr_log1.created_at < usr_log2.created_at
                WHERE
                    usr_log2.user_id IS NULL) 
                AS temp';

    DB::table('users as usr')
        ->select(...)
        ->leftJoin(DB::raw($subquery), 'usr.id', '=', 'temp.user_id')
        ->leftJoin(...)
        ->join(...)
        ->join(...)
        ->join(...)
        ->leftJoin(...)
        ->leftJoin(...)
        ->leftJoin(...)
        ->where(...)
        ->get()

这些问题中有类似的例子：

Laravel Fluent Query Builder Join with subquery

How to write this (left join, subquery ) in Laravel 5.1?

更多信息abaut加入： https://laravel.com/docs/5.5/queries#joins

Answer 2

感谢所有回答的用户，经过几次测试后，我选择使用带有原始查询的DB :: table，并且效果非常好

谢谢大家。

Answer 3

您可以尝试完全针对此案例设计的Eloquent extension enabling subqueries inside eloquent。

在你的样本中它将是

User::selectRaw(....)
->leftJoinSubquery(UserLogs::where(...)->leftJoin(...),
    'temp', 
    function ($join) {
        $join->on('users.id', '=', 'temp.user_id');
    }
)

加入laravel的子查询

3 个答案: