我有一个从键盘输入不同于0和随机数k的随机数的赋值。我需要找到奇数+ k的总和(如果k也是奇数)。此外,当仅在键入0时键入数字时,数字的键入将被中断。这就是我到目前为止所拥有的!
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
class Program
{
static void Main()
{
int k;
int min;
int max;
int odd = 0;
Console.WriteLine("Enter the value of k: ");
k = int.Parse(Console.ReadLine());
Console.WriteLine("Enter minimum integer: ");
min = int.Parse(Console.ReadLine());
Console.WriteLine("Enter maximum integer: ");
max = int.Parse(Console.ReadLine());
Console.Write("Odd: ");
for (int x = min; x <= max; x++)
{
if (x % 2 != 0)
{
Console.Write(x);
Console.Write(" + ");
odd += x;
}
}
Console.WriteLine();
Console.Write("Odd Numbers + K: ");
Console.WriteLine();
{
if (k % 2 !=0)
{
Console.Write(k);
Console.Write(" + ");
odd += k;
}
}
Console.Write("= ");
Console.Write(odd + "\n");
}
}
答案 0 :(得分:-2)
此代码可满足您的需求。它检查界限最小值和最大值。当输入零时它结束,它也保持奇数的总和。
用这个替换你的静态void Main()函数。
static void Main()
{
//int k;
int min;
int max;
int odd = 0;
Console.WriteLine("Enter minimum integer: ");
min = int.Parse(Console.ReadLine());
Console.WriteLine("Enter maximum integer: ");
max = int.Parse(Console.ReadLine());
Console.WriteLine("Enter your number: ");
bool userIsTyping = true;
while (userIsTyping)
{
Console.WriteLine("Enter another number: ");
int userNumber = int.Parse(Console.ReadLine());
if (userNumber == 0)
{
userIsTyping = false;
}
else if (userNumber > max)
{
Console.WriteLine("The number is out of bounds: greater than max.");
}
else if (userNumber < min)
{
Console.WriteLine("The number is out of bounds: less than min.");
}
else
{
if (userNumber % 2 != 0)
{
odd += userNumber;
Console.WriteLine("Current Total: " + odd.ToString());
}
else
{
Console.WriteLine("That is not an odd number.");
}
}
}
Console.WriteLine("The final result is: " + odd.ToString());
Console.ReadLine();
}