我想将此数据数组过滤为州和城市数组。我怎样才能使用lodash或任何其他更好的方式实现这一点,而不是循环和维护额外的数组。
data: [
{ id: 1, name: Mike, city: philps, state: New York},
{ id: 2, name: Steve, city: Square, state: Chicago},
{ id: 3, name: Jhon, city: market, state: New York},
{ id: 4, name: philps, city: booket, state: Texas},
{ id: 5, name: smith, city: brookfield, state: Florida},
{ id: 6, name: Broom, city: old street, state: Florida},
]
用户点击state
,会显示状态列表。
{state: New York, count: 2},
{state: Texas, count: 1},
{state: Florida, count: 2},
{state: Chicago, count: 1},
当用户单击特定状态时,将显示该状态的cities
列表。对于前者当用户点击纽约州时,
{id:1, name: Mike, city: philps}
{id:3, name: Jhon, city: market}
答案 0 :(得分:10)
您可以使用native
javascript来执行此操作,方法是接受参数 filter
提供的功能。
callback

另一种方法是使用let data= [ { id: 1, name: 'Mike', city: 'philps', state:'New York'}, { id: 2, name: 'Steve', city: 'Square', state: 'Chicago'}, { id: 3, name: 'Jhon', city: 'market', state: 'New York'}, { id: 4, name: 'philps', city: 'booket', state: 'Texas'}, { id: 5, name: 'smith', city: 'brookfield', state: 'Florida'}, { id: 6, name: 'Broom', city: 'old street', state: 'Florida'}, ]
data = data.filter(function(item){
return item.state == 'New York';
}).map(function({id, name, city}){
return {id, name, city};
});
console.log(data);
函数。
arrow

答案 1 :(得分:4)
使用Array.prototype.filter
,Array.prototype.map
,Array.prototype.reduce
和解构非常简单:
//filter by particular state
const state = /*the given state*/;
const filtered = data
.filter(e => e.state == state)//filter to only keep elements from the same state
.map(e => {
const {id, name, city} = e;
return {id, name, city};
});//only keep the desired data ie id, name and city
//get states array
const states = data
.reduce((acc, elem) => {
const state_names = acc.map(e => e.state);//get all registered names
if(state_names.includes(elem.state)){//if it is already there
const index = acc.find(e => e.state==elem.state);
acc[index] = {state: acc[index].state, count: acc[index].count+1};//increment it's count
return acc;
}else//otherwise
return [...acc, {state: elem.state, count: 1}];//create it
}, []);
参见this jsfiddle,了解它的实际效果。
答案 2 :(得分:4)
使用lodash,您可以将_.filter
与对象一起用作 _.matches
iteratee简写,以使用给定的键/值对过滤对象
var data = [{ id: 1, name: 'Mike', city: 'philps', state: 'New York' }, { id: 2, name: 'Steve', city: 'Square', state: 'Chicago' }, { id: 3, name: 'Jhon', city: 'market', state: 'New York' }, { id: 4, name: 'philps', city: 'booket', state: 'Texas' }, { id: 5, name: 'smith', city: 'brookfield', state: 'Florida' }, { id: 6, name: 'Broom', city: 'old street', state: 'Florida' }];
console.log(_.filter(data, { state: 'New York' }));
console.log(_
.chain(data)
.countBy('state')
.map((count, state) => ({ state, count }))
.value()
);
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>
答案 3 :(得分:3)
仅遵循过滤器功能 例如
return data.filter(data => data.state == "New York" && count === 2);