我的程序确实在一个litteral数字中转换了一个int。 它准确地使用大于（-9999）的数字或小于9999的数字但是当我输入12314115151作为用户输入时，程序打印一个＆＃34;否定的＃34;。我想我的代码中出错并需要你的帮助..
这是我的代码：
#include <stdio.h>
#include <conio.h>
void positive(int input, int t);
void negative(int input, int t);
void main(){
int input,t;
clrscr();
textcolor(YELLOW);
cprintf("ENTER YOUR NUMBER: ");
scanf("%i",&input);
if (input < -9999 || input > 9999){
textcolor(RED);
cprintf("\nINVALID ENTRY, PROGRAM TERMINATED");
}
else if(input == 0){
cprintf("\nNUMBER IN WORD(S): ");
printf("Zero");
}
else if(input < 0 || input >-10000){
cprintf("\nNUMBER IN WORD(S): ");
negative(input,t);
}
else if(input > 0 || input <10000){
cprintf("\nNUMBER IN WORD(S): ");
positive(input,t);
}
getch();
}
void positive(int input, int t){
char* a[11]={"","One","Two","Three","Four","Five","Six","Seven","Eeight","Nine","Ten"};
char* b[10]={"","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
char* c[10]={"","","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety"};
textcolor(WHITE);
if(input > 0 || input < 11){
t=input/1;
cprintf("Positive %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf("Positive %s",b[t]);
}
if (input > 19 || input < 100){
t = input/10;
cprintf("Positive %s",c[t]);
t=input%10;
cprintf(" %s",a[t]);
}
if (input > 99 || input < 1000){
t =input/100;
cprintf("Positive %s Hundred",a[t]);
t*=100;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
}
if(input >999 || input <10000){
t=input/1000;
cprintf("Positive %s Thousand",a[t]);
t*=1000;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
if(input > 99 || input < 1000){
t=input/100;
cprintf(" %s Hundred",a[t]);
t*=100;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
}
}
return;
}
void negative(int input, int t){
char* a[11]={"","One","Two","Three","Four","Five","Six","Seven","Eeight","Nine","Ten"};
char* b[10]={"","Eleven","Twelve","Thirteen","Fourteen","Fifteen","Sixteen","Seventeen","Eighteen","Nineteen"};
char* c[10]={"","","Twenty","Thirty","Fourty","Fifty","Sixty","Seventy","Eighty","Ninety"};
textcolor(WHITE);
input*=-1;
if(input > 0 || input < 11){
t=input/1;
cprintf("Negative|| %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf("Negative %s",b[t]);
}
if (input > 19 || input < 100){
t = input/10;
cprintf("Negative %s",c[t]);
t=input%10;
cprintf(" %s",a[t]);
}
if (input > 99 || input < 1000){
t =input/100;
cprintf("Negative %s Hundred",a[t]);
t*=100;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
}
if(input >999 || input <10000){
t=input/1000;
cprintf("Negative %s Thousand",a[t]);
t*=1000;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
if(input > 99 || input < 1000){
t=input/100;
cprintf(" %s Hundred",a[t]);
t*=100;
input-=t;
if(input > -1 || input < 11){
t=input/1;
cprintf(" and %s",a[t]);
}
if(input > 10 || input < 20){
t=input%10;
cprintf(" and %s",b[t]);
}
if (input > 19 || input < 100)
{
t=input/10;
cprintf(" and %s",c[t]);
input=input%10;
cprintf(" %s",a[input]);
}
}
}
return;
}
有什么想法吗？
答案 0 :(得分：1)
else if(input == 0){
cprintf("\nNUMBER IN WORD(S): ");
printf("Zero");
}
else if(input < 0 || input >-10000){ // There should be && instead of ||.
cprintf("\nNUMBER IN WORD(S): ");
negative(input,t);
}
else if(input > 0 || input <10000){ //There too.
cprintf("\nNUMBER IN WORD(S): ");
positive(input,t);
}
如您所见，我已评论您应编辑哪些代码部分。现在您正在寻找大于-10000 的数字 - 您的数字 IS 更高。 num＆lt; 0并不意味着什么，因为它现在是可选条件。如下所述，
12314115151不是有效的32位int值
答案 1 :(得分：0)
如果你改变你的情况，你会得到理想的结果：
else if(input < 0){
cprintf("\nNUMBER IN WORD(S): ");
negative(input,t);
}
else if(input > 0){
cprintf("\nNUMBER IN WORD(S): ");
positive(input,t);
}