Question

我有用于并行读取员工，地址和联系人文件并将其转换为beanIO对象并合并beanIO对象以生成完整的employeeDetails对象。

Emp档案：

1 Foo Engineer
2 Bar AssistantEngineer

Emp联系人文件：

1 8912345678  foo@org.com
2 7812345678    bar@org.com

Emp地址文件：

 1 city1 1234
 2 city2 2345

Exchange中EmployeeDetailsBeanIODataFormat对象的预期输出：

1 Foo Engineer foo@org.com city1 1234
2 Bar AssistantEngineer bar@org.com city2 2345

我有以下路线

from("file://C:/cameltest/employee.txt").to("seda:beanIO");
from("file://C:/cameltest/employeeContact.txt").to("seda:beanIOContact");
from("file://C:/cameltest/employeeAddress.txt").to("seda:beanIOAddress");

每个文件都转换为beanio对象

BeanIODataFormat empFormat = new BeanIODataFormat("beanIO.xml","emp");
BeanIODataFormat empContactFormat = new BeanIODataFormat("beanIO.xml", "empContact");
BeanIODataFormat empAddressFormat = new BeanIODataFormat("beanIO.xml", "empAddress");

from("seda:beanIO").unmarshal(empFormat).log("body - ${body}");        
from("seda:beanIOContact").unmarshal(empContactFormat).log("Contact body ${body}");
from("seda:beanIO").unmarshal(empAddressFormat).log("Address body - ${body}");

输出正确记录bean对象。

现在我需要合并对象以形成EmployeeDetails对象。有人能告诉我怎么做吗？我已经阅读过，似乎聚合器可以用来完成这项工作，但不确定这种方法。

对样本的任何想法都会有所帮助。建议是受欢迎的，建议首先根据员工ID合并文件并从中创建一个对象吗？在这种情况下，我不想将合并文件写入磁盘，因为IO会降低性能。

先谢谢。

Answer 1

在解组后使用拆分器拆分每条消息

from("seda:beanIO").unmarshal(empFormat).split(body()).to("seda:aggregate");
from("seda:beanIOContact").unmarshal(empContactFormat).split(body()).to("seda:aggregate");
from("seda:beanIOAddress").unmarshal(empAddressFormat).split(body()).to("seda:aggregate");

接下来是聚合器的外观。 details对象存储为olddExchange中的标头。最重要的参数如下

correlationExpression：simple（＆＃34; $ {body.id}＆＃34;）关联所有具有相同ID（1或2）的邮件
completionSize = 3。每个文件一个。

from("seda:aggregate").aggregate(simple("${body.id}"), (oldExchange,newExchange) -> {
        if (oldExchange == null) {
            EmployeeDetails details = buildDetails(new EmployeeDetails(), newExchange);
            newExchange.getIn().setHeader("details", details);
            return newExchange;
        }
        EmployeeDetails details = oldExchange.getIn().getHeader("details", EmployeeDetails.class);
        buildDetails(details, newExchange);
        oldExchange.getIn().setHeader("details", details);
        return oldExchange;
    }).completionSize(3).log("Details - ${header.details}")

并且

private EmployeeDetails buildDetails(EmployeeDetails details, Exchange newExchange) {
        Object newBody = newExchange.getIn().getBody();
        if (newBody instanceof Employee) {
            details.setId(((Employee) newBody).getId());
            details.setName(((Employee) newBody).getName());
            details.setJob(((Employee) newBody).getJob());
        } else if (newBody instanceof EmployeeContact) {
            details.setEmail(((EmployeeContact) newBody).getEmail());
        } else if (newBody instanceof EmployeeAddress) {
            details.setCity(((EmployeeAddress) newBody).getCity());
            details.setCode(((EmployeeAddress) newBody).getCode());
        }
        return details;
    }

然后结果将是2个细节对象

Details - EmployeeDetails(id=1, name=Foo, job=Engineer, email=foo@org.com, city=city1, code=1234)
Details - EmployeeDetails(id=2, name=Bar, job=AssistantEnginee, email=bar@org.com, city=city2, code=2345)

Apache Camel：文件到BeanIO并基于id合并beanIO对象

1 个答案: