Question

select opening_balances.branch_ID, opening_balances.comm_ID, 
 (ifnull(comm_issue.comm_issue_quantity,0) - ifnull(comm_sales.comm_sale_quantity,0)) AS net,
 (opening_balances.comm_quantity + net) AS Closing_Balance
 FROM opening_balances
JOIN comm_sales JOIN comm_issue
ON opening_balances.branch_ID = ifnull(comm_sales.branch_ID,0) = ifnull(comm_issue.branch_ID,0) = opening_balances.branch_ID 
&& opening_balances.comm_ID = ifnull(comm_sales.comm_ID,0) = opening_balances.comm_ID = ifnull(comm_issue.comm_ID,0) ;

我需要获得如上所示的期末余额。

Answer 1

鉴于您的数据

drop table if exists opening_balances,comm_sales,comm_issue;


create table Opening_balances 
(`Date` date, branch_ID int, comm_ID int, comm_quantity int);
insert into opening_balances values
 ('2017-11-01',1,1,5), ('2017-11-01',1,2,6), ('2017-11-01',2,1,7), ('2017-11-01',2,2,8),
 ('2017-11-01',3,2,10);

create table comm_sales 
(branch_ID int, comm_ID int, comm_sale_quantity int, `Date` datetime);
insert into comm_sales values
 (1,1,3,'2017-10-19 11:03:15'), (1,2,3,'2017-10-19 11:03:30'), (2,1,3,'2017-10-19 11:03:37'), (2,2,4,'2017-10-19 11:03:42');

create table comm_issue 
(branch_ID int, comm_ID int, comm_issue_quantity int, `Date` datetime);
insert into comm_issue values
 (1,1,3,'2017-10-21 04:37:05');

你的查询似乎试图通过branch和comm_id来获得一些总数。如果是这种情况，我希望看到一些聚合函数（sum）和group by。也许就像这样

select ob.branch_id, ob.comm_id,
         coalesce(sum(ob.comm_quantity),0) OpeningQTY,
         Coalesce(sum(ci.comm_issue_quantity),0) IssueQty,
         coalesce(sum(cs.comm_sale_quantity),0) SaleQty,
         coalesce(sum(ci.comm_issue_quantity),0) - coalesce(sum(cs.comm_sale_quantity),0) net,
         coalesce(sum(ob.comm_quantity),0)  +
         coalesce(sum(ci.comm_issue_quantity),0) - 
         coalesce(sum(cs.comm_sale_quantity),0) ClosingQty
from opening_balances ob
left join comm_sales cs on cs.branch_id = ob.branch_id and cs.comm_id = ob.comm_id
left join comm_issue ci on ci.branch_id = ob.branch_id and ci.comm_id = ob.comm_id
group by ob.branch_id , ob.comm_id 

+-----------+---------+------------+----------+---------+------+------------+
| branch_id | comm_id | OpeningQTY | IssueQty | SaleQty | net  | ClosingQty |
+-----------+---------+------------+----------+---------+------+------------+
|         1 |       1 |          5 |        3 |       3 |    0 |          5 |
|         1 |       2 |          6 |        0 |       3 |   -3 |          3 |
|         2 |       1 |          7 |        0 |       3 |   -3 |          4 |
|         2 |       2 |          8 |        0 |       4 |   -4 |          4 |
|         3 |       2 |         10 |        0 |       0 |    0 |         10 |
+-----------+---------+------------+----------+---------+------+------------+
5 rows in set (0.02 sec)

如果您想获得小计，可以使用汇总添加到查询的末尾

    select ob.branch_id, ob.comm_id,
             coalesce(sum(ob.comm_quantity),0) OpeningQTY,
             Coalesce(sum(ci.comm_issue_quantity),0) IssueQty,
             coalesce(sum(cs.comm_sale_quantity),0) SaleQty,
             coalesce(sum(ci.comm_issue_quantity),0) - coalesce(sum(cs.comm_sale_quantity),0) net,
             coalesce(sum(ob.comm_quantity),0)  +
             coalesce(sum(ci.comm_issue_quantity),0) - 
             coalesce(sum(cs.comm_sale_quantity),0) ClosingQty
    from opening_balances ob
    left join comm_sales cs on cs.branch_id = ob.branch_id and cs.comm_id = ob.comm_id
    left join comm_issue ci on ci.branch_id = ob.branch_id and ci.comm_id = ob.comm_id
    group by ob.branch_id , ob.comm_id with rollup;

+-----------+---------+------------+----------+---------+------+------------+
| branch_id | comm_id | OpeningQTY | IssueQty | SaleQty | net  | ClosingQty |
+-----------+---------+------------+----------+---------+------+------------+
|         1 |       1 |          5 |        3 |       3 |    0 |          5 |
|         1 |       2 |          6 |        0 |       3 |   -3 |          3 |
|         1 |    NULL |         11 |        3 |       6 |   -3 |          8 |
|         2 |       1 |          7 |        0 |       3 |   -3 |          4 |
|         2 |       2 |          8 |        0 |       4 |   -4 |          4 |
|         2 |    NULL |         15 |        0 |       7 |   -7 |          8 |
|         3 |       2 |         10 |        0 |       0 |    0 |         10 |
|         3 |    NULL |         10 |        0 |       0 |    0 |         10 |
|      NULL |    NULL |         36 |        3 |      13 |  -10 |         26 |
+-----------+---------+------------+----------+---------+------+------------+
9 rows in set (0.00 sec)

这是什么解决方案？

1 个答案: