Question

下面的代码读取文件系统并将JSON对象返回到php页面，然后将其解析出来。

我正在尝试添加一个“Questions”属性，该属性读取csv文件

“$ .FullName +”\“+ $ .Name +”-questions.csv“

并返回一个JSON对象，该对象将嵌套在父对象中。现在它只返回一个“[”。不知道为什么？任何帮助

Param(
    [Parameter(Mandatory = $true)][string]$path
)
function Add-Tabstops{
    param($Count)
    $tabs = ""
    for($i=0; $i -lt $Count; $i++){$tabs += "  "}
    return $tabs
}
function Read-Questions($name){
    $name = $name + "-questions.csv"
    if(Test-Path($name)){
        $questions= Import-CSV $name | ConvertTo-JSON
        return "["
                $questions
                "]"
    }
    else{
        return "None"
    }
}
function Process-Path{
     param($Path)
     if (Test-Path "$path"){
        $source = $path.Split("\")
        $source = $source[($source.Length -1)]
        Output-JsonChildren -Path "$path" -Source $source
     }
     else {
        return '"No Objects Found!"'
     }
}

function Output-JsonChildren{
    param($Path, $Level = 1, $Source)
    return $(Get-ChildItem -Path $Path -Directory | Where-Object{$_} | ForEach-Object{
        (Add-Tabstops $Level) +
        "{`n" + 
        (Add-Tabstops ($Level+1)) +
        "`"Name`"`: `"$($_.Name)`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Image`"`: `"$($_.Name)`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"displayName`"`: `"$((Get-Content($($_.FullName + "\" + $_.Name + ".txt"))).split('-')[0])`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Attribute1`"`: `"$((Get-Content($($_.FullName + "\" + $_.Name + ".txt"))).split('-')[1])`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Attribute2`"`: `"$((Get-Content($($_.FullName + "\" + $_.Name + ".txt"))).split('-')[2])`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Attribute3`"`: `"$((Get-Content($($_.FullName + "\" + $_.Name + ".txt"))).split('-')[3])`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Attribute4`"`: `"$Source`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) +
        "`"Questions`"`: `"$(Read-Questions($($_.FullName + "\" + $_.Name)))`"," + 
        "`n" +
        (Add-Tabstops ($Level+1)) + 
        "`"children`": ["+ 
        $(if($_.psiscontainer){"`n" + (Output-JsonChildren -Path $_.FullName -Level ($Level+2))+ "`n" + (Add-Tabstops ($Level+1))}) +
        "]`n" + 
        (Add-Tabstops ($Level)) +
        "}"
    }) -join ",`n"
}

$JSON = Process-Path -Path $path

"["
$JSON
"]"

Answer 1

您的代码：

return "["
        $questions
        "]"

让我们将这三行和一些分号重新格式化为显式行结尾，但保持功能相同：

return "[";
$questions;
"]";

这是否清楚说明为什么函数总是返回[？

你想：

return '[' + $Questions.ToString() + ']';

Powershell脚本读取文件系统和csv文件并返回JSON对象？

1 个答案: