Question

我想要一个仅用于探索和寻找选项的转弯计数器。并将它添加到当前时代。我怎样才能做到这一点？我正在使用python 2.7。以下是代码的重要部分：

from main import name
import os
import random


kenyan_sand_boa = {
    "snek": "kenyan sand boa",
    "prey": "mice, " "birds, " "lizards",
    "biome": "desert",
    "predators": "desert monitor lizard",
    "adult age": 156,
    "baby size": 10,
    "adult size": 20,
    "current size": 10,
    "current age": "0",
    "name": name,
}


os.system('cls')
def menu():
        os.system('cls')
        print '''Now that you have chosen what snek to be, you have a couple 
options
1. Read info about kenyan sand boas.
2. Explore.
3. Hunt.
4. View inventory.
5. Save.
6. Exit.
'''

loop = 1
choice = 0
while loop == 1:
    menu()
    choice = int(raw_input())

    if choice == 1:
        #information about kenyan sand boas
    if choice == 2:
        #exploring
    if choice == 3:
        #huntinng
    if choice == 4:
        #view inventory
    else:
        menu()

Answer 1

初始化turn=0

在您的探索/搜寻案例中，添加以下内容：

turn = turn+1 
kenyan_sand_boa["current age"] = kenyan_sand_boa["current age"]+1

可能必须将年龄定义为int，因为它当前是一个字符串，但是这样的代码将在您完成后完成工作。

Answer 2

在while代码集中，转为0。

while loop == 1:
    turn = 0
    menu()
    # ...

由于您也在增加年龄，因此最好将"current age"设置为0而不是"0"。在您的狩猎和探索"current age"条款中，将turn和if增加一个。（使用elif代替更多pythonic）

elif choice == 2:
    turn += 1
    kenyan_sand_boa["current age"] += 1
    # exploring
elif choice == 3:
    turn += 1
    kenyan_sand_boa["current age"] += 1
    # hunting

如何在python 2.7中计算转数

2 个答案: