Question

我非常感谢能帮助解决我的问题。

请帮助我在网上寻找工作或类似的例子，但找不到任何东西。

我已收到以下xml导入我们的系统：

<Address addressOrg="Import">
<Name>Sams Shop</Name>
<AddressOrg>01 Red Road</AddressOrg>
<AddressOrg>Summer Town</AddressOrg>
<City></City>
<Province></Province>
<Postcode></Postcode>
<Country>
<CountryCode></CountryCode>
</Country>
<AccountNumber></AccountNumber>
</Address>
<Address addressOrg="Exporter">
<Name>PToms Shop</Name>
<AddressOrg>01 Blue Road</AddressOrg>
<AddressOrg>Snow Town</AddressOrg>
<City></City>
<Province></Province>
<Postcode></Postcode>
<Country>
<CountryCode></CountryCode>
</Country>
<AccountNumber></AccountNumber>
</Address>

我正在尝试完成下面的xslt：

<OrgsAddressCollection>
          <OrganizationAddress>
            <AddressType>ConsigneeDeliveryAddress</AddressType>
            <Address1><xsl:value-of select="Address/AddressOrg"/></Address1>
            <Address2><xsl:value-of select="Address/AddressOrg"/></Address2>
            <CompanyName><xsl:value-of select="Address/Name"/>/CompanyName>
            <Fax />
            <OrganizationCode />
            <Phone />
          </OrganizationAddress>
          <OrganizationAddress>
            <AddressType>ConsignorDDeliveryAddress</AddressType>
            <Address1><xsl:value-of select="Address/AddressOrg"/></Address1>
            <Address2><xsl:value-of select="Address/AddressOrg"/></Address2>
            <CompanyName><xsl:value-of select="Address/Name"/></CompanyName>
            <Fax />
            <OrganizationCode />
            <Phone />
          </OrganizationAddress>
<OrgsAddressCollection>

上述问题是因为标签名称与第一个相同当我使用上面的代码引用它时，地址数据集似乎也在拉到第二个地址。

我希望上面的xslt输出以下转换后的结果：

<OrgsAddressCollection>
          <OrganizationAddress>
            <AddressType>ConsigneeDeliveryAddress</AddressType>
            <Address1>01 Red Road</Address1>
            <Address2>Summer Town</Address2>
            <CompanyName>Sams Shop</CompanyName>
            <Fax />
            <OrganizationCode />
            <Phone />
          </OrganizationAddress>
          <OrganizationAddress>
            <AddressType>ConsignorDDeliveryAddress</AddressType>
            <Address1>01 Blue ROad</Address1>
            <Address2>Snow Town</Address2>
            <CompanyName>Toms Shop</CompanyName>
            <Fax />
            <OrganizationCode />
            <Phone />
          </OrganizationAddress>
<OrgsAddressCollection>

Answer 1

执行<xsl:value-of select="Address/AddressOrg" />只会获得第一个Address元素，以及第一个AddressOrg。

也许您的案例中只会有两个地址，但要避免过多的重复编码，并使其更加灵活，您可以在此使用xsl:for-each（或xsl:apply-templates）

<xsl:for-each select="Address">
  <OrganizationAddress>

并且，在此范围内，您可以通过在方括号中指定相关元素的位置来获得两个AddressOrd元素（请注意您现在所在的xsl:for-each和Address元件）

<Address1><xsl:value-of select="AddressOrg[1]"/></Address1>
<Address2><xsl:value-of select="AddressOrg[2]"/></Address2>

要根据输入自定义某些输出标签，您还可以使用xsl:choose。

试试这个XSLT片段

<OrgsAddressCollection>
  <xsl:for-each select="Address">
    <OrganizationAddress>
      <AddressType>
         <xsl:choose>
            <xsl:when test="@addressOrg = 'Import'">ConsigneeDeliveryAddress</xsl:when>
            <xsl:when test="@addressOrg = 'Exporter'">ConsignorDDeliveryAddress</xsl:when>
        </xsl:choose>
      </AddressType>
      <Address1><xsl:value-of select="AddressOrg[1]"/></Address1>
      <Address2><xsl:value-of select="AddressOrg[2]"/></Address2>
      <CompanyName><xsl:value-of select="Name"/></CompanyName>
      <Fax />
      <OrganizationCode />
      <Phone />
    </OrganizationAddress>
  </xsl:for-each>
</OrgsAddressCollection>

引用重复标记

1 个答案: