Question

大家好我正在尝试使用以下

创建一个门锁

var gpio = require("pi-gpio");
var gpioPin = 4; 
var isOpened=false; 
var unlock = function(){ 
if(!isOpened){
/* Open the door lock */
gpio.write(gpioPin, 1, function() {
isOpened = true;
});
/*Lock door in 2 seconds*/
setTimeout(function () {
gpio.write(gpioPin, 0, function() {
isOpened = false;
});
}, 2000);}}

然后是以下内容：

var http = require('http'); var express = require('express');
var app = express();
var GPIOCtrl = require('./controller.js');
app.get('/unlock/', function(req, res){ 
GPIOCtrl.unlock();
});
app.listen(3000); 
console.log('App Server running at port 3000');

当我运行程序时，我得到消息应用服务器在端口3000运行，但是当我调用它时，我收到以下消息：

TypeError: GPIOCtrl.unlock is not a function

我做错了什么？

Answer 1

您必须在controller.js：

中export模块中library

var gpio = require("pi-gpio"),
  gpioPin = 4,
  isOpened = false,

module.exports = {
  unlock: function() {
    if (!isOpened) {
      /* Open the door lock */
      gpio.write(gpioPin, 1, function() {
        isOpened = true;
      });

      /*Lock door in 2 seconds*/
      setTimeout(function() {
        gpio.write(gpioPin, 0, function() {
          isOpened = false;
        });
      }, 2000);
    }
  }
}

RPI上的Javascript：GPIOCtrl不是一个函数

1 个答案: